What is the difference between internal hardware and software?
1 answer:
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Answer:
Check the explanation
Explanation:
Note : check attached image for output and program and also note that you're to replace "at" with shift 2 as the brainly text editor can't take the symbol
Program : **************Magzine.java**********************
/*
* To change this license header, choose License Headers in Project Properties.
* To change this template file, choose Tools | Templates
* and open the template in the editor.
*/
public class Magzine {
//class variable private can not access outside class
private String title;
private String month;
private int year;
//parameterized constructor
public Magzine(String title,String month,int year)
{
this.title=title;
this.month=month;
this.year=year;
}
//override toString method
"at"Override
public String toString()
{
String detail=title+" "+month+" "+Integer.toString(year);
return detail;//return string of class variable
}
//get Magzine objecte
public boolean equals(Magzine obj)
{
//commented returm statement compare string by address so you can uncomment if
//we do not use same string object of String class
//return this.month==obj.month && this.title==obj.title && this.year==obj.year;
//compare two object element if matches return true else false
return (this.month.equals(obj.month)) &&(this.title.equals(obj.title)) && this.year==obj.year;
}
}
Program : *************************Main.java****************************
/*
* To change this license header, choose License Headers in Project Properties.
* To change this template file, choose Tools | Templates
* and open the template in the editor.
*/
public class Main {
/**
* "at"param args the command line arguments
*/
public static void main(String[] args) {
// TODO code application logic here
Magzine Obj =new Magzine("Scientific American ", "April", 2020); //object of class
Magzine Obj1 =new Magzine("Scientific American ", "April", 2020);//Obj and obj1 is same content data
Magzine Obj2 =new Magzine("Scientific American", "June", 2020); //obj and obj1 same but obj2 different
System.out.println(Obj.toString()); //print string of obj
System.out.println(Obj1.toString());//print string of obj1
System.out.println(Obj2.toString());//print string of obj2
System.out.println(Obj.equals(Obj1)); //obj and obj1 equal and return true
System.out.println(Obj.equals(Obj2)); // obj and obj2 not equal so return false
}
}
Output can be seen below:
Answer:
Explanation:
The following code is written in Java. It uses for loops to loop through the array of characters, and uses IF statements to check if the symbols in the expression are balanced. If so it returns true, otherwise it breaks the function and returns false. Two test cases have been provided in the main method and the output can be seen in the attached image below.
import java.util.ArrayList;
class Brainly {
public static void main(String[] args) {
char[] exp = { '[', 'A', '*', '{', 'B', '(', 'C', 'D', ')', '}', ']'};
char[] exp2 = {'[', 'A', '*', '(', 'C', '}', ']'};
System.out.println(checkBalance(exp));
System.out.println(checkBalance(exp2));
}
public static boolean checkBalance(char exp[]) {
ArrayList<Character> symbols = new ArrayList<>();
for (char x: exp) {
if ((x =='[') || (x == '{') || (x == '(')) {
symbols.add(x);
}
if (x ==']') {
if (symbols.get(symbols.size()-1) == '[') {
symbols.remove(symbols.size()-1);
} else {
return false;
}
}
if (x =='}') {
if (symbols.get(symbols.size()-1) == '{') {
symbols.remove(symbols.size()-1);
} else {
return false;
}
}
if (x ==')') {
if (symbols.get(symbols.size()-1) == '(') {
symbols.remove(symbols.size()-1);
} else {
return false;
}
}
}
return true;
}
}
