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umka21 [38]
3 years ago
15

NEED HELP FINDING SOME COORDINATES

Mathematics
1 answer:
IgorC [24]3 years ago
5 0

Answer:

The image of (7,2) is (2,12)

Step-by-step explanation:

First you need to find the translation vector.

Let the translation vector be u=(a,b). Then the translation rule is

(x,y)\to (x+a,y+b).

From the equation, the image of P(2,-4) is  P'(-3,6).When we apply this rule using the translation vector, we get

P(2,-4)\to P'(2+a,-4+b)

Now we have

P'(2+a,-4+b)=P'(-3,6)

We can therefore equate corresponding coordinates

2+a=-3 and -4+b=6

This implies that:

a=-3-2 and b=6+4

a=-5 and b=10

Hence our translation vector is u=(-5,10)

The translation rule now becomes:

(x,y)\to (x-5,y+10).

To find the image of (7,2), we plug it into the translation rule.

(7,2)\to (7-5,2+10).

(7,2)\to (2,12).

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