Plzzz help .........

Mathematics

2 answers:

Murrr4er [49]2 years ago

7 0

I feel that A is the answer.
Hope this helps

velikii [3]2 years ago

3 0

C. sounds like the most reasonable answer to the question.<span />

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g If there are 52 cards in a deck with four suits (hearts, clubs, diamonds, and spades), how many ways can you select 5 diamonds

dezoksy [38]

Answer:

The number of ways to select 5 diamonds and 3 clubs is 368,082.

Step-by-step explanation:

In a standard deck of 52 cards there are 4 suits each consisting of 13 cards.

Compute the probability of selecting 5 diamonds and 3 clubs as follows:

The number of ways of selecting 0 cards from 13 hearts is:

${13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1$

The number of ways of selecting 3 cards from 13 clubs is:

${13\choose 3}=\frac{13!}{3!\times(13-3)!} =\frac{13!}{13!\times10!}=286$

The number of ways of selecting 5 cards from 13 diamonds is:

${13\choose 5}=\frac{13!}{5!\times(13-5)!} =\frac{13!}{13!\times8!}=1287$

The number of ways of selecting 0 cards from 13 spades is:

${13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1$

Compute the number of ways to select 5 diamonds and 3 clubs as:

${13\choose0}\times{13\choose3}\times{13\choose5}\times{13\choose0} = 1\times286\times1287\times1=368082$

Thus, the number of ways to select 5 diamonds and 3 clubs is 368,082.

6 0

2 years ago

The perimeter of a rectangular painting is 244 centimeters. If the width of the painting is 51 centimeters, what is the length?

Schach [20]

Answer:

193 i think

Step-by-step explanation:

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6 0

3 years ago

Can someone help me on trigonometry ?

Olenka [21]

Using the image I gave you, you don't need to solve for x.
So tan is opposite/adjacent
sin: opposite/hypotenuse
cos: adjacent/hypotenuse
Take theta and do: adjacent/hypotenuse which is cosine
cos theta = adjacent/hypotenuse
cos theta = 1.5/9
inverse cos = 1.5/9 and the answer is: 80.4 degrees