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max2010maxim [7]
3 years ago
10

Plzzz help .........

Mathematics
2 answers:
Murrr4er [49]3 years ago
7 0
I feel that A is the answer.
Hope this helps
velikii [3]3 years ago
3 0
C. sounds like the most reasonable answer to the question.<span />
You might be interested in
Which property can be used to expand the expression -2(3/4*+7)?
nika2105 [10]

Answer:

C. The distributive property

Step-by-step explanation:

The distributive property of binary activities is generalized in mathematics by the distributive law of Boolean algebra and elementary algebra. Distribution applies, in propositional logic, to two clear substitution laws. The rules allow one to reformulate, within logical facts, conjunctions and disjunctions.

7 0
2 years ago
Which of the following proportions could be used to find x?
OLga [1]

\frac{x}{2} = \frac{6}{1.5}

The 2 right triangles are similar and so the ratios of corresponding sides are equal

The corresponding sides are x and 2, 6 and 1.5, hence

\frac{x}{2} = \frac{6}{1.5}


5 0
3 years ago
Katie bought 2 one-gallon bottles of juice for a party. Her guests drank 6/4 gallons of juice. What fraction of a gallon of juic
Alenkasestr [34]
6/4 = 1 1/2 gallons 
2 - 1 1/2 = 1/2 gallon

She has 1/2 a gallon left over


3 0
3 years ago
Read 2 more answers
5/8 + 3/4 divided by -2/3 - 5/6
exis [7]
-1.5 should be your answer.
if wrong I apologize.
5 0
3 years ago
On a particular production line, the likelihood that a light bulb is defective is 10%. seven light bulbs are randomly selected.
amid [387]

Answer:

0.9995

Step-by-step explanation:

10% = 0.10

1 - 0.10 = 0.9

n = number of light bulbs = 7

we calculate this using binomial distribution.

p(x) = nCx × p^x(1-p)^n-x

our question says at most 4 is defective

= (7C0 × 0.1⁰ × 0.9⁷) + (7C1 × 0.1¹ × 0.9⁶) + (7C2 × 0.1² × 0.9⁵) + (7C3 × 0.1³ × 0.9⁴) + (7C4 × 0.1⁴ × 0.9³)

= 0.478 + 0.372 + 0.1239 + 0.023 + 0.0026

= 0.9995

we have 0.9995 probability that at most 4 light bulbs are defective.

6 0
3 years ago
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