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mart [117]
3 years ago
13

Corey records the temperature in degrees Celsius each morning. At 8am the temperature was 3 degrees below zero. It rose 3 degree

s by 10am. Which equation shows the change in temperature from 8am to 10am?
A 3+3=6
B-3+3=0
C-3+3= -6
D-3-3= -6​
Mathematics
1 answer:
Finger [1]3 years ago
3 0
B

It was 3 degrees below so the 3 will be a negative 3. Then by 10 it rose up by 3 so it is a positive 3. So -3+3=0
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7/8 × c for c = 8 algebra
Aleonysh [2.5K]
You would do 7/8 x 8/1 which is 56/8 which simplifys to 7 so your answer would be 7

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3 years ago
Please help me I don't have a lot of time<br> tan(30)=a/2
Ludmilka [50]

Answer:

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5 0
4 years ago
What is a formula for the nth term of the given sequence?<br> 36, 24, 16...
SpyIntel [72]

Answer:

The formula to find the nth term of the given sequence is 54 · \frac{2}{3} ^{n}

Step-by-step explanation:

The formula for nth term of an geometric progression is :

a_{n} = \frac{a_{1}(r^{n})}{r}

In this example, we have a_{1} = 36 (the first term in the sequence) and

r = \frac{2}{3} (the rate in which the sequence is changing).

Knowing what the values for r and a_{1} are, now we can solve.

a_{n} = \frac{a_{1}(r^{n})}{r} = \frac{36 (\frac{2}{3} ^{n}) }{\frac{2}{3} } = 54 · \frac{2}{3} ^{n}

Therefore, the formula to find the nth term of the given sequence is

54 · \frac{2}{3} ^{n}

3 0
3 years ago
According to a survey, the average American person watches TV for 3 hours per week. To test if the amount of TV in New York City
Neporo4naja [7]

Answer:

Test statistic (t-value) of this one-mean hypothesis test is -2.422.

Step-by-step explanation:

We are given that according to a survey, the average American person watches TV for 3 hours per week. She surveys 19 New Yorkers randomly and asks them about their amount of TV each week, on average. From the data, the sample mean time is 2.5 hours per week, and the sample standard deviation (s) is 0.9 hours.

We have to test if the amount of TV in New York City is less than the national average.

Let Null Hypothesis, H_0 : \mu \leq 3  {means that the amount of TV in New York City is less than the national average}

Alternate Hypothesis, H_1 : \mu > 3   {means that the amount of TV in New York City is more than the national average}

The test statistics that will be used here is One-sample t-test statistics;

        T.S. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample mean time = 2.5 hours per week

             s = sample standard deviation = 0.09 hours

             n = sample size = 19

So, <u>test statistics</u> = \frac{2.5 - 3}{\frac{0.9}{\sqrt{19} } } ~ t_1_8

                              = -2.422

Therefore, the test statistic (t-value) of this one-mean hypothesis test (with σ unknown) is -2.422.

8 0
4 years ago
Solve 8/t+5 = t-3/t+5 + 1/3
Aleks04 [339]

\frac{8}{t}  + 5 = t -  \frac{3}{t}  + 5 +  \frac{1}{3}  \\  \\ 1. \:  \frac{8}{t} =  -  \frac{3}{t} +  \frac{1}{3}   \\  \\ 2. \: 24 = 3t^{2}  - 9 + t \\  \\ 3. \: 24 - 3t^{2} + 9 - t = 0 \\  \\ 4. \: 33 - 3t ^{2}- t = 0 \\  \\ 5. \: t =  \frac{1 +  \sqrt{397} }{ - 6}  \:  \frac{1 -  \sqrt{397} }{ - 6}  \\  \\ 6. \: t =  -  \frac{1 +  \sqrt{397} }{6}  \:  -  \frac{1 -  \sqrt{397} }{6}

7 0
4 years ago
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