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marin [14]
3 years ago
8

Solve the equation with substitution 3x-2y=9 Y=2x-7

Mathematics
1 answer:
stich3 [128]3 years ago
3 0
3x-2y=9 \\
y=2x-7 \\ \\
\hbox{substitute 2x-7 for y in the 1st equation:} \\
3x-2(2x-7)=9 \\
3x-4x+14=9 \\
-x+14=9 \ \ \ |-14 \\
-x=-5 \ \ \ |\times (-1) \\
x=5 \\ \\
y=2x-7=2 \times 5-7=10-7=3 \\ \\
\boxed{(x,y)=(5,3)}
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y = -0.0976(x - 10)^2 + 18, x \geq 0

The graph is given at the end of the answer.

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The equation of a quadratic function, of vertex (h,k), is given by:

y = a(x - h)^2 + k

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In this problem, the maximum value was a share value of $18 after 10 days, hence the vertex is:

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