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n200080 [17]
3 years ago
15

Ivan purchased stock in a company at an initial price of $8 per share. The share value reached $18 after 10 days and then began

to decrease. He found that the stock’s value over time was best modeled with a quadratic function. Which graph best represents his model of the relationship between stock value and time?
Mathematics
1 answer:
Butoxors [25]3 years ago
6 0

The quadratic equation that best represents his model of the relationship between stock value and time is given by:

y = -0.0976(x - 10)^2 + 18, x \geq 0

The graph is given at the end of the answer.

<h3>What is the equation of a parabola given it’s vertex?</h3>

The equation of a quadratic function, of vertex (h,k), is given by:

y = a(x - h)^2 + k

In which a is the leading coefficient.

In this problem, the maximum value was a share value of $18 after 10 days, hence the vertex is:

(h,k) = (10,18).

Thus:

y = a(x - 10)^2 + 18

Since the initial price was of $8 per share, we have that:

8 = a(0 - 10)^2 + 18

-82a = 8

a = -\frac{8}{82}

a = -0.0976

Hence the equation is:

y = -0.0976(x - 10)^2 + 18, x \geq 0

At the end of the answer, the sketch of the graph is given.

More can be learned about quadratic equations at brainly.com/question/24737967

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\begin{cases} -x+3y=9\\\\ y=\cfrac{2}{3}x \end{cases} \\\\[-0.35em] ~\dotfill\\\\ -x+3y=9\implies 3y=9+x\implies \underline{3y-9=x} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{substituting ont the 2nd equation}}{y=\cfrac{2}{3}(\underline{3y-9})\implies 3y=2(3y-9)}\implies 3y=6y-18\implies 18+3y=6y \\\\\\ 18=3y\implies \cfrac{18}{3}=y\implies \boxed{6=y}

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Use the frequency table to determine how many students received a score of 80 or better on an English exam.
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10 students scored above an 80
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What does g =??? <br> 2/5g = 5
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.........................
maria [59]

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lol

Step-by-step explanation:

8 0
3 years ago
A simple random sample of 110 analog circuits is obtained at random from an ongoing production process in which 20% of all circu
telo118 [61]

Answer:

64.56% probability that between 17 and 25 circuits in the sample are defective.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 110, p = 0.2

So

\mu = E(X) = np = 110*0.2 = 22

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{110*0.2*0.8} = 4.1952

Probability that between 17 and 25 circuits in the sample are defective.

This is the pvalue of Z when X = 25 subtrated by the pvalue of Z when X = 17. So

X = 25

Z = \frac{X - \mu}{\sigma}

Z = \frac{25 - 22}{4.1952}

Z = 0.715

Z = 0.715 has a pvalue of 0.7626.

X = 17

Z = \frac{X - \mu}{\sigma}

Z = \frac{17 - 22}{4.1952}

Z = -1.19

Z = -1.19 has a pvalue of 0.1170.

0.7626 - 0.1170 = 0.6456

64.56% probability that between 17 and 25 circuits in the sample are defective.

4 0
4 years ago
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