4 years ago

Angelique says that finding the absolute value of a number is the same as finding the opposite

1 answer:

4 0

If you're asking if that statement is correct... then yes it is.

Example: The absolute value of -1 is 1. And the absolute value of 1 is -1.

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According to the school survey 12% of the students at Rockwood high school speak Spanish there are 36 students at the school who

Svet_ta [14]

36 - 12%
x - 100%

$x=\frac{100\%\cdot36}{12\%}\\
x=300$

6 0

3 years ago

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Evaluate each expression for r=9 n t=14 enter in your numerical answer

Neko [114]

Answer:

1764

Step-by-step explanation:

$from \: the \: question \: rt {}^{2} \\ were \: r =9 \\ and \: t = 14 \\ rt {}^{2} = 9 \times (14) {}^{2} = 9 \times 196 = 1764$

3 0

2 years ago

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Help how many questions did you answer correctly

Lady bird [3.3K]

Answer:

450

Step-by-step explanation:

you divide 90 by 20 and times in by 100

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3 years ago

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What is the quotient 2y^-6y-20/4y+12 ÷ y+5y+6/3y^2+28y+27

malfutka [58]

Answer with explanation:

$\rightarrow \frac{\frac{2y^2-6 y-20}{4 y+12}}{\frac{y^2+5 y+6}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{y^2-3y-10}{2 y+6}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{(y-5)(y+2)}{2 (y+3)}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{(y-5)(y+2)}{2 (y+3)}} \times {\frac{3 y^2+28 y+27}{(y+2)(y+3)}}\\\\ \rightarrow\frac{(y-5)\times(3 y^2+28 y+27)}{2 (y+3)^2}}$

→y²+5y+6

=y²+3 y+2 y+6

=y×(y+3)+2×(y+3)

=(y+2)(y+3)

→y² -3 y-10

=y² -5 y+2 y -10

=y×(y-5)+2×(y-5)

=(y+2)(y-5)

6 0

3 years ago

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The triangle below is an equilateral triangle. Find y.<br> 10<br> y+3

Colt1911 [192]

Answer:

y = 7

Step-by-step explanation:

An equilateral triangle has all its sides to be equal..

so.

10 = x

10 = y + 3

y = 10 - 3

y = 7

6 0

3 years ago