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4 years ago

15

Angelique says that finding the absolute value of a number is the same as finding the opposite

1 answer:

frutty [35]4 years ago

4 0

If you're asking if that statement is correct... then yes it is.

Example: The absolute value of -1 is 1. And the absolute value of 1 is -1.

You might be interested in

18X - 15+13X - 11+4x + 1=180 <br> what’s x?

bezimeni [28]

Answer: x equals forty one over five

Step-by-step explanation: Add the numbers 18x-15+3x-11+4x+1=180 18x-25+3x+4x=180 then you combine like terms and you get, 18x-25+3x+4x=180 25x-25=180 then you add 5 to both sides of the equation 25x-25=180. 25x-25+25=180+25 then you simplify then you add the numbers 25x=205 then you divide both sides of the equation by the same term 25x=205 25x/25 = 205/25 then you simplify, you cancel terms that are in both the numerator and denominator then you divide the numbers and you get, x equals forty one over five.

3 0

3 years ago

3x^2-12x factorise in the form (x+b)(x-b)

Alekssandra [29.7K]

Answer:

$3x(x-4)$

Step-by-step explanation:

$3x^2-12x$ cannot be factorised in the form (x+b)(x-b) unless one of the b's is zero, so I wonder if the expression is incomplete?

To factorise $3x^2-12x$ , take out the common factor $3x$ :

$\implies3x(x-4)$

Therefore, x = 0 and x = 4

- - - - - - - - -

$3x^2-12x$ factorised in the form (x+b)(x-b) would be $(3x+0)(x-4)$

but it is not usual to have a zero in a factorised form.

5 0

2 years ago

Vera wants to graph a line that passes through (0,2) and has a slope of 2/3 which points could Vera use to graph a line check al

Naddik [55]

The answer to the question

6 0

3 years ago

Read 2 more answers

Which ordered pair is a solution to the inequality 7x-3y>10?

OlgaM077 [116]

it ain't possible.

unless Either X's value is given for u to get y.

6 0

3 years ago

two square regions have an area of 125 and 5 how many yards of fencing is needed to enclose? ( assume regions fenced separately)

nadya68 [22]

Answer:

$24\sqrt{5}\ yards$

Step-by-step explanation:

Let A1 be the area of one square and A2 be the area of second square

So,

A1 = s^2

where s is side of square

$s^2=125\\\sqrt{s^2}=\sqrt{125}\\s=\sqrt{25*5}\\ s= \sqrt{5^2 * 5}\\ s= 5\sqrt{5}$

So side of one square is $5\sqrt{5}$

To calculate the length of fence we need to find the perimeter of the square

So,

P1 = 4 * s

$=4*5\sqrt{5} \\=20\sqrt{5}$

For second square:

$A_2=s^2\\5=s^2\\\sqrt{s^2}=5\\{s}=\sqrt{5}$

The perimeter will be:

$P_2 = 4*s\\=4 * \sqrt{5} \\=4\sqrt{5}$

So the total fence will be: P1+P2

$= 20\sqrt{5}+4\sqrt{5} \\= 24\sqrt{5}\ yards$

3 0

3 years ago