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serg [7]
2 years ago
11

(5 •10^16) • (2.8 • 10^-7)

Mathematics
1 answer:
Gelneren [198K]2 years ago
7 0
That's 7/3 =2.3333333
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Equation:
puteri [66]

Answer:

the answer is 988 .........

7 0
3 years ago
Solve the System of Equations
Softa [21]

<u>Answer: </u>

The ordered pair value of (x, y) is (6,-11)

<u>Solution: </u>

Given Equations are

Let 8x + 15y = -117 be Equation 1 and 4x + 9y=-75 be Equation 2.

Solving Equations 1 and 2 to get the value of x and y.

Multiply Equation 2 with 4.

16x + 36y = -300

On dividing the above expression by 2, we get

8x + 18y = -150 (Change the sign to get the value of y).  

-8x - 18y = 150 --- eqn 3

Now solving eqn 1 and eqn 3

8x + 15y = -117

-8x - 18y = 150  

By cancelling 8x and -8x in eqn 1 and eqn 3

-3y = 33    

 y = -11

Substitute the value y in Equation 2.

4x + 9 (-11) = -75

4x – 99 = - 75

4x= -75 +99

4x = 24

x=6

Hence the value of x and y is (6,-11).

3 0
3 years ago
Let (8,−3) be a point on the terminal side of θ. Find the exact values of cosθ, cscθ, and tanθ.
denis23 [38]

Answer:

\text{Cos}\theta=\frac{\text{Adjacent side}}{\text{Hypotenuse}}=\frac{x}{R}=\frac{8}{\sqrt{73}}

\text{Csc}\theta=-\frac{\sqrt{73}}{3}

\text{tan}\theta =\frac{\text{Opposite side}}{\text{Adjacent side}}=\frac{y}{x}=\frac{-3}{8}

Step-by-step explanation:

From the picture attached,

(8, -3) is a point on the terminal side of angle θ.

Therefore, distance 'R' from the origin will be,

R = \sqrt{x^{2}+y^{2}}

R = \sqrt{8^{2}+(-3)^2}

  = \sqrt{64+9}

  = \sqrt{73}

Therefore, Cosθ = \frac{\text{Adjacent side}}{\text{Hypotenuse}}=\frac{x}{R}=\frac{8}{\sqrt{73}}

Sinθ = \frac{\text{Opposite side}}{\text{Hypotenuse}}=\frac{y}{R}=\frac{-3}{\sqrt{73} }

tanθ = \frac{\text{Opposite side}}{\text{Adjacent side}}=\frac{y}{x}=\frac{-3}{8}

Cscθ = \frac{1}{\text{Sin}\theta}=\frac{R}{y}=-\frac{\sqrt{73}}{3}

6 0
3 years ago
The manager of a grocery store wants to determine the average amount of money spent at his store as it compares to the average d
dexar [7]

Given

Expenditures at Manager's Store; expenditures at Competitor's Store.

Find

a) average spent at each store

b) which store is better represented by the mean value

c) an explanation for the answer in ≥ 2 sentences

Solution

a) The sum of expenditures divided by the number of expenditures (15) is ...

... average for Manager's Store: $37.60

... average for Competitor's Store: $48.53

b) The expenditures at Manager's Store are well-represented by the mean (average).

c) The range of expenditures at Competitor's Store is significantly higher than at Manager's store, so a single number such as mean or median does not represent the data well. The expenditures at Manager's store are more compactly grouped around the mean and median, which are closer together, so the mean is a good representation of Manager's Store expenditures overall.

4 0
3 years ago
Mayra's monthly salary is $4,540 plus she earns an 8% commission on her sales each month. Mayra's sales for January were $30,000
lesantik [10]
Work out 8% of 30000

10% of 30000 is 3000

1% of 30000 is 300
2% of 30000 is 300x2=600

Therefore 10%-2%= 3000-600=2400

It therefore follows that Mayra earned 4540 + 2400 = 6940 for January

7 0
3 years ago
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