3 years ago

Which ratio is equivalent to 10 : 85

2 answers:

3 0

Multiply both numerator and denominator by 2
10 X 2 = 20 
85 X 2 = 170 

so 20 / 170

Tomtit [17]3 years ago

3 0

2 : 17 is the ratio equivalent to 10 : 85

You might be interested in

Multiplying Monomials and Binomials multiply 15w(w+15)

sleet_krkn [62]

The answer is 15w^2 + 225w

Key:

^ - Means that it is an exponent, in case you didn't know :)

3 0

3 years ago

ABCD∼EFGH

DerKrebs [107]

45/75 = 30/x

30*75 = 2250/45 = 50

EF = 50 in.

6 0

3 years ago

Read 2 more answers

You know that 15% of a number n is 12. How can you use this to find 30% of n? 45% of n? Explain.

Keith_Richards [23]

30% is 24
45% is 36
take 15% and multiply it by however much it takes to make the percentage than multiply that by 12

5 0

3 years ago

Help fast I need real answers thanks

BaLLatris [955]

What is the question?

4 0

3 years ago

Read 2 more answers

Use l'Hôpital's Rule to find the following limit. ModifyingBelow lim With x right arrow 0StartFraction 3 sine (x )minus 3 x Ove

steposvetlana [31]

Answer:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=-\frac{1}{14}$

Step-by-step explanation:

The limit is:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{0}{0}$

so, you have an indeterminate result. By using the l'Hôpital's rule you have:

$\lim_{x \to 0} \frac{a(x)}{b(x)}= \lim_{x \to 0} \frac{a'(x)}{b'(x)}$

by replacing, and applying repeatedly you obtain:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}= \lim_{x \to 0}\frac{3cosx-3}{21x^2}= \lim_{x \to 0}\frac{-3sinx}{42x}= \lim_{x \to 0}\frac{-3cosx}{42}\\\\ \lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{-3cos0}{42}=-\frac{1}{14}$

hence, the limit of the function is -1/14

8 0

3 years ago