Total weight of the steel gate = 150 kg
Solution:
Length = 12 m
Breadth = 5 m
Using Pythagoras theorem,
Diagonal =
Diagonal = 13 m
Total length of the gate = 5 + 5 + 12 + 12 + 13 + 13
Total length of the gate = 60 m
Weight of the steel per meter = 2.5 kg
Weight of the steel for 60 m = 60 × 2.5
= 150 kg
Total weight of the steel gate = 150 kg
Answer:
Step-by-step explanation:
Given data
Total units = 250
Current occupants = 223
Rent per unit = 892 slips of Gold-Pressed latinum
Current rent = 892 x 223 =198,916 slips of Gold-Pressed latinum
After increase in the rent, then the rent function becomes
Let us conside 'y' is increased in amount of rent
Then occupants left will be [223 - y]
Rent = [892 + 2y][223 - y] = R[y]
To maximize rent =
Since 'y' comes in negative, the owner must decrease his rent to maximixe profit.
Since there are only 250 units available;
Optimal rent - 838 slips of Gold-Pressed latinum