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erma4kov [3.2K]
3 years ago
7

1.Factor

Mathematics
2 answers:
bezimeni [28]3 years ago
5 0

1.  Factor out the (y-4)

(y-4) (3x-2)


2.Factor by grouping

20xy -4y    +35x -7

4y(5x-1) +7(5x-1)

then factor out 5x-1

(5x-1)(4y+7)

Alina [70]3 years ago
3 0

(1)

take out the common factor (y - 4 )

= (y - 4)(3x - 2)

(2)

factor by grouping (1/2 terms and 3/4 terms )

4y(5x - 1) + 7(5x - 1)

take out the common factor (5x - 1)

= (5x - 1)(4y + 7)



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An example problem in a Statistics textbook asked to find the probability of dying when making a skydiving jump.
MArishka [77]

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(a) 0.999664

(b) 15052

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From the given data of recent years,  there were about 3,000,000 skydiving jumps and 21 of them resulted in deaths.

So, the probability of death is \frac{21}{3000000}==0.000007.

Assuming, this probability holds true for each skydiving and does not change in the present time.

So, as every skydiving is an independent event having a fixed probability of dying and there are only two possibilities, the diver will either die or survive, so, all skydiving can be regarded as is Bernoulli's trial.

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q=7\times 10^{-6}=0.000007.

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(a) The total number of jump he made, n=48

Using Bernoulli's equation, the probability of surviving in exactly 48 jumps (r=48) out of 48 jumps (n=48) is

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So, the probability of survive in 48 skydiving is 0.999664,

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Let, total n skydiving jumps required to meet the surviving probability of 0.9.

So, By using Bernoulli's equation,

0.9=\binom {n }{r} p^rq^{n-r}

Here, r=n.

\Rightarrow 0.9=\binom{n}{n}p^nq^{n-n}

\Rightarrow 0.9=p^n

\Rightarrow 0.9=(0.999993)^n

\Rightarrow \ln(0.9)=n\ln(0.999993) [ taking \log_e both sides]

\Rightarrow n=\frac {\ln(0.9)}{\ln(0.999993)}

\Rightarrow n=15051.45

The number of diving cant be a fractional value, so bound it to the upper integral value.

Hence, the total number of skydiving required to meet the 90% probability of surviving is 15052.

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Step-by-step explanation:

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