Answer:
H0: μ = 5 versus Ha: μ < 5.
Step-by-step explanation:
Given:
μ = true average radioactivity level(picocuries per liter)
5 pCi/L = dividing line between safe and unsafe water
The recommended test here is to test the null hypothesis, H0: μ = 5 against the alternative hypothesis Ha: μ < 5.
A type I error, is an error where the null hypothesis, H0 is rejected when it is true.
We know type I error can be controlled, so safer option which is to test H0: μ = 5 vs Ha: μ < 5 is recommended.
Here, a type I error involves declaring the water is safe when it is not safe. A test which ensures that this error is highly unlikely is desirable because this is a very serious error. We prefer that the most serious error be a type I error because it can be explicitly controlled.
Here are the outcomes. You could also a tree diagram for this:
There are 49 outcomes for this problem. Therefore, 7/49 possible probability that 2 could be orange. To check if i'm correct, use a tree diagram or a compound principle.
Answer:
The answer is Option D:
<em>"The distribution of all values of the statistic resulting from all samples of size taken from the same population."</em>
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Step-by-step explanation:
First, is a distribution of all values. It has to include all the possible values of the statistic with its associated probability.
Second, is a distribution of a statistic because we are talking about sample results.
Third, it has to be taken from the same population and have to have the same sample size.
I think it's -35. The steps to get that number is subtracting the 3 to the right side. Then you have -2 - 3 which equals to -5. Then you still have x/7= -5. Get rid of 7 from the x and do the same thing to the other side but you multiply 7 and -5. Last you your would be x= -35.
