All categories

2 years ago

Endpoint P(5, -3) and Q(2,4)

Mathematics

1 answer:

NikAS [45]2 years ago

4 0

The midpoint of these two points would be (3.5, 0.5)

In order to find this, you need to take the average of the two point that you have. To do that, add the numbers together and divide by 2. Start with just the x values.

(5 + 2)/2 = 3.5

Now the y values

(-3 + 4)/2 = 0.5

This gives us the ordered pair of (3.5, 0.5)

You might be interested in

Add then divide.<br> Evaluate<br> (7.3 X 10) + (2.4 X 107)<br> (4 X 104)

Deffense [45]

Answer:

6.0 x 10^2

Step-by-step explanation:

(7.3 X 10) + (2.4 X 10^7)

(4 X 10^4)

= 73 + 24000000

40000

= 24000073

40000

= 6.0 x 10^2

4 0

2 years ago

<img src="https://tex.z-dn.net/?f=2%20%5Ctimes%202" id="TexFormula1" title="2 \times 2" alt="2 \times 2" align="absmiddle" class

EastWind [94]

4 (i literally had to think about this cause i thought it was too easy )

6 0

2 years ago

What is a gradient of a line

Dennis_Churaev [7]

(slope) The higher the gradient<span> of a graph at a point, the steeper the </span>line<span> is at that point.</span>

4 0

2 years ago

Read 2 more answers

A 6.50% coupon bond with 18 years left to maturity is offered for sale at $1,035.25. What yield to maturity [interest rate] is t

Basile [38]

Answer:

The yield to maturity is 6.3974%

Step-by-step explanation:

The computation of the yield to maturity is as follows

Given that

NPER = 18 × 2 = 36

PMT = $1,035.25 × 6.50% ÷ 2 = $33.65

PV = $1,035.25

FV = $1,000

The formula is shown below:

=RATE(NPER;PMT;-PV;FV;TYPE)

The present value comes in negative

AFter applying the above formula, the yield to maturity is

= 3.1987% × 2

= 6.3974%

Hence, the yield to maturity is 6.3974%

7 0

2 years ago

3. How many solutions does the system of equations have? 2x=-10y+ 6 and x+5y=3

ozzi

Answer:

<h2>3. Infinitely many</h2>

Step-by-step explanation:

$\left\{\begin{array}{ccc}ax+by=c\\dx+ey=f\end{array}\right\\\\(1)\\\text{if}\ a=d,\ b=e,\ c=f,\ \text{then the system of equations has infinitely many solutions}\\Example:\\\left\{\begin{array}{ccc}2x-3y=5\\2x-3y=5\end{array}\right\\(2)\\\text{if}\ a=d,\ b=e,\ c\neq f,\ \text{then the system of equations has no solution}\\Example:\\\left\{\begin{array}{ccc}2x-3y=5\\2x-3y=-5\end{array}\right$

$(3)\\\text{if}\ a\neq d\ \text{or}\ b\neq e,\ \text{then the system of equations has infinitely many solutions}\\Example:\\\left\{\begin{array}{ccc}x-3y=5\\2x-3y=5\end{array}\right$

$\text{We have:}\\\\\left\{\begin{array}{ccc}2x=-10y+6&\text{add 10y to both sides}\\x+5y=3\end{array}\right\\\left\{\begin{array}{ccc}2x+10y=6&\text{divide both sides by 2}\\x+5y=3\end{array}\right\\\left\{\begin{array}{ccc}x+5y=3\\x+5y=3\end{array}\right$

4 0

2 years ago