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mariarad [96]
3 years ago
7

Rewrite the equation to identify the center of the circle and the radius.

Mathematics
1 answer:
Hatshy [7]3 years ago
8 0
Standard Form : ( x - 1 ) ^2 + ( y + 3 ) ^2 = 5
Center of the circle : ( 1 , -3 )
Radius: line mark over 5
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A local bottler in Hawaii wishes to ensure that an average of 22 ounces of passion fruit juice is used to fill each bottle. In o
Mandarinka [93]

Answer:

(a) Null Hypothesis, H_0 : \mu = 22 ounces  

    Alternate Hypothesis, H_A : \mu\neq 22 ounces

(b) The value of the test statistic is -2.687.

(c) The critical values are -1.96 and 1.96.

(d) We conclude that Reject H_0 since the value of the test statistic is less than the negative critical value.

Step-by-step explanation:

We are given that a local bottler in Hawaii wishes to ensure that an average of 22 ounces of passion fruit juice is used to fill each bottle.

He takes a random sample of 65 bottles. The mean weight of the passion fruit juice in the sample is 21.54 ounces. Assume that the population standard deviation is 1.38 ounce.

<em>Let </em>\mu<em> = average ounces of passion fruit juice used to fill each bottle.</em>

(a) So, Null Hypothesis, H_0 : \mu = 22 ounces     {means that the average of 22 ounces of passion fruit juice is used to fill each bottle}

Alternate Hypothesis, H_A : \mu\neq 22 ounces     {means that the average different from 22 ounces of passion fruit juice is used to fill each bottle}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;

                        T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean weight of the passion fruit juice = 21.54 ounces

            \sigma = population standard deviation = 1.38 ounce

            n = sample of bottles = 65

So, <u><em>test statistics</em></u>  =  \frac{21.54-22}{\frac{1.38}{\sqrt{65} } }  

                               =  -2.687

(b) The value of z test statistics is -2.687.

(c) Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

<em>Since our test statistics does not lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><u><em>we reject our null hypothesis</em></u><em>.</em>

Therefore, we conclude that Reject H_0 since the value of the test statistic is less than the negative critical value which means that the average different from 22 ounces of passion fruit juice is used to fill each bottle.

6 0
3 years ago
A United Nations report shows the mean family income for Mexican migrants to the United States is $27,000 per year. A FLOC (Farm
disa [49]

Answer:

We conclude that the mean family income for Mexican migrants to the United States is $27,000 per year and the provided information is consistent with the United Nations report.

Step-by-step explanation:

We are given that a United Nations report shows the mean family income for Mexican migrants to the United States is $27,000 per year.

A FLOC  evaluation of 25 Mexican family units reveals a mean to be $30,000 with a sample standard deviation of $10,000.

Let \mu = <em><u>true mean family income for Mexican migrants.</u></em>

So, Null Hypothesis, H_0 : \mu = $27,000     {means that the mean family income for Mexican migrants to the United States is $27,000 per year}

Alternate Hypothesis, H_A : \mu \neq $27,000     {means that the mean family income for Mexican migrants to the United States is different from $27,000 per year}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                          T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean family income = $30,000

            s = sample standard deviation = $10,000

            n = sample of Mexican family = 25

So, <u><em>the test statistics</em></u>  =  \frac{30,000-27,000}{\frac{10,000}{\sqrt{25} } }  ~ t_2_4

                                     =  1.50

The value of t test statistics is 1.50.

Since, in the question we are not given the level of significance so we assume it to be 5%. <u>Now, at 5% significance level the t table gives critical values of -2.064 and 2.064 at 24 degree of freedom for two-tailed test.</u>

Since our test statistic lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that the mean family income for Mexican migrants to the United States is $27,000 per year and the provided information is consistent with the United Nations report.

4 0
3 years ago
What is the image of the point (6, -4) when rotated 180 degrees anticlockwise about the origin?
icang [17]

Answer:

What is the image of the point (6, -4) when rotated 180 degrees anticlockwise about the origin?

(-6, -4)

(-6, 4)

(4, 6)

(-4, -6)

the answer is (-6, 4).

8 0
3 years ago
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A rectangle has a length of x inches and a width of y inches
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3 0
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A can of soda weighs 336 grams. find the weight in kilograms of 20 cans.
jolli1 [7]
20 cans in kilograms = 336 grams * 20 cans / 1000 = 6.72 kg
8 0
3 years ago
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