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2 years ago

Solve for w 7w+6w-8+2=4w+9w-8+2

Mathematics

2 answers:

Rainbow [258]2 years ago

8 0

Step-by-step explanation:

Given

7w + 6w - 8 + 2 = 4w + 9w - 8 + 2

Combining like terms

9w + 4w - 7w - 6w = - 8 +2 + 8 - 2

13w - 13w = 0

0 = 0

Snowcat [4.5K]2 years ago

3 0

Answer:

infinite solutions

Step-by-step explanation:

7w+6w-8+2=4w+9w-8+2 Combine like terms

13w - 6 = 13w -6

Infinite solutions meaning no matter what term w is, they will always equal each other.

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Q # 2 Graph TWX and it's image after a rotation of 90° counterclockwise about the origen

const2013 [10]

<span>For a rotation of 90o: (x, y) ⇒ (–y, x)
T(3,4) ⇒⇒⇒ T'(-4,3)
W(-2,-1) ⇒⇒⇒ W'(1,-2)
x(-3,3) ⇒⇒⇒ x'(-3,-3)

see the attached figure

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6 0

3 years ago

Our faucet is broken, and a plumber has been called. The arrival time of the plumber is uniformly distributed between 1pm and 7p

Ymorist [56]

Answer:

$E(A+B) = E(A)+E(B)=4+0.5 =4.5 hours$

$Var(A+B)= Var(A)+Var(B)=3+0.25 hours^2=3.25 hours^2$

Step-by-step explanation:

Let A the random variable that represent "The arrival time of the plumber ". And we know that the distribution of A is given by:

$A\sim Uniform(1 ,7)$

And let B the random variable that represent "The time required to fix the broken faucet". And we know the distribution of B, given by:

$B\sim Exp(\lambda=\frac{1}{30 min})$

Supposing that the two times are independent, find the expected value and the variance of the time at which the plumber completes the project.

So we are interested on the expected value of A+B, like this

$E(A +B)$

Since the two random variables are assumed independent, then we have this

$E(A+B) = E(A)+E(B)$

So we can find the individual expected values for each distribution and then we can add it.

For ths uniform distribution the expected value is given by $E(X) =\frac{a+b}{2}$ where X is the random variable, and a,b represent the limits for the distribution. If we apply this for our case we got:

$E(A)=\frac{1+7}{2}=4 hours$

The expected value for the exponential distirbution is given by :

$E(X)= \int_{0}^\infty x \lambda e^{-\lambda x} dx$

If we use the substitution $y=\lambda x$ we have this:

$E(X)=\frac{1}{\lambda} \int_{0}^\infty y e^{-\lambda y} dy =\frac{1}{\lambda}$

Where X represent the random variable and $\lambda$ the parameter. If we apply this formula to our case we got:

$E(B) =\frac{1}{\lambda}=\frac{1}{\frac{1}{30}}=30min$

We can convert this into hours and we got E(B) =0.5 hours, and then we can find:

$E(A+B) = E(A)+E(B)=4+0.5 =4.5 hours$

And in order to find the variance for the random variable A+B we can find the individual variances:

$Var(A)= \frac{(b-a)^2}{12}=\frac{(7-1)^2}{12}=3 hours^2$

$Var(B) =\frac{1}{\lambda^2}=\frac{1}{(\frac{1}{30})^2}=900 min^2 x\frac{1hr^2}{3600 min^2}=0.25 hours^2$

We have the following property:

$Var(X+Y)= Var(X)+Var(Y) +2 Cov(X,Y)$

Since we have independnet variable the Cov(A,B)=0, so then:

$Var(A+B)= Var(A)+Var(B)=3+0.25 hours^2=3.25 hours^2$

3 0

3 years ago

Given 2x+4y=12 what is the x and y int

Setler [38]

Both are 2! 2x2=4 4x2=8 so 8+4=12

3 0

2 years ago

Use the distributive property to evaluate the expression.

JulijaS [17]

Answer:

208 or 26(8)

Step-by-step explanation:

8*26=208

26*8=208

6 0

3 years ago

I need help with this question!!

IrinaVladis [17]

Answer:

I'm pretty sure it's (0,1)

8 0

2 years ago