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tamaranim1 [39]
4 years ago
13

A rectangular poster is 3 times as long as it is wide. A rectangular banner is 5 times as it is wide. Both the banner and the po

ster have perimeters of 24 inches. What are the lengths and widths of the poster and the banner?
Mathematics
1 answer:
Svetradugi [14.3K]4 years ago
8 0

The length and width of poster are 9 inches and 3 inches respectively and length and width of banner are 10 inches and 2 inches respectively

<u> Solution:</u>

Given, A rectangular poster is 3 times as long as it is wide.  

Rectangular banner is 5 times as long as it is wide.  

Both the banner and the poster have perimeters of 24 inches

Let, the width of poster be p, then its length will be 3p

And, the width of banner be b, then its length will be 5b

Now, according to given information,

Perimeter of poster = 24 inches and perimeter of banner = 24 inches

2(length of poster + width of poster) = 24

2(3p + p) = 24

2(4p) = 24

8p = 24

p = 3

And 2(length of banner + width of banner) = 24

2(5b + b) = 24

2(6b) = 24

12b = 24

b = 2

So, width of poster is 3 inches, then length of poster is 3p = 3 x 3 = 9 inches

And, width of banner is 2 inches, then length of banner is 5b = 5 x 2 = 10 inches

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Answer:

yes

Step-by-step explanation:

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2 years ago
What are the solution(s) to the quadratic equation x² - 25 = 0?
gtnhenbr [62]

Answer:

x = ±5

Step-by-step explanation:

x² - 25 = 0

x² = 25

√x² = √25

x = ±5

Check:

5² - 25 = 0

-5² - 25 = 0

25 - 25 = 0

4 0
1 year ago
A bank quotes an interest rate as 0.06341 annual effective yield. What interest rate, compounded monthly, will provide that
Leviafan [203]

9514 1404 393

Answer:

  0.06164

Step-by-step explanation:

The effective annual rate obtained by compounding nominal annual rate r monthly is ...

  eff rate = (1 +r/12)^12 -1

Then the value of r is ...

  r = 12×((eff rate) +1)^(1/12) -1)

For the given effective rate, that is ...

  r = 12×(1.06341^(1/12) -1) ≈ 0.06164 . . . . nominal annual interest rate

4 0
3 years ago
1- un tinaco se llena en 8 horas utilizando 4 llaves. en cuanto tiempo se llenara con 7 llaves?
svetoff [14.1K]

Answer: 4.6 horas.

Step-by-step explanation:

Podemos calcular el tiempo necesario por una llave:

si sabemos que se llena en 8 horas con 4 llaves, entonces una sola llave va a tardar 4 veces 8 horas en llenar el tinaco, es decir, una sola llave tarda:

4*8h = 32 horas

ahora, si usamos 7 llaves, el tiempo necesario va a ser un septimo de eso:

(32 h por llave)/(7 llaves) = 32/7 horas = 4.6 horas.

4 0
3 years ago
stion 1 OT 5A researcher recorded the number of swans and the number of ducks in a lake every month. Function s represents the n
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Given functions are

s(n)=2(1.1)^n+5_{}d(n)=4(1.08)^n+3

The total number of ducks and swans in the lake after n months can be determined by adding the functions s(n) and d(n).

t(n)=s(n)+d(n)

t(n)=(2(1.1)^n^{}+5)+(4(1.08)^n+3)

t(n)=2(1.1)^n+5+4(1.08)^n+3

t(n)=2(1.1)^n+4(1.08)^n+5+3

t(n)=2(1.1)^n+4(1.08)^n+8

Taking 2 as common, we get

t(n)=2\lbrack(1.1)^n+2(1.08)^n+4\rbrack

Hence The total number of ducks and swans in the lake after n months is

t(n)=2\lbrack(1.1)^n+2(1.08)^n+4\rbrack

8 0
1 year ago
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