Answer:
For the first question, 180 degrees equals to a half of the sphere. For the second question, you need 24 central meridians for a complete sphere, which are exactly the hours in a day.
Step-by-step explanation:
A sphere is basically a 3D circle. As a circle has 360 degrees, 180 degrees would be half of a circle. Imagine you are on a satellite over the north pole or the south pole and you have a way to cut the earth by the middle. You will get two halves of sphere.
About the second question, you may need to have in mind that a day is the time spent for the earth to rotate all 360 degrees over its own axis. British fellow, on XIX century, decided they were the center of the world. As previously, back in the days, some other people decided a day had 24 hours, they decided to draw this lines and divide the earth in 24 pieces, so they could knew which time was on every point their extense kingdom had. As I said, a circle has 360 degrees, (360 degrees)/(24 hours) equals to 15 degrees.
Answer:
6660 yards^2
Step-by-step explanation:
Assumption: the field is 120 yards long and 50 yards wide.
First calculate the area of the field: 120*50 = 6000 yards^2
Then, calculate the 11% of that area: 6000 yards^2*11/100 = 660 yards^2
Finally, the area of the tarp material should be 6000 yards^2 + 660 yards^2 = 6660 yards^2
Responder:
24 litros; 16 litros; 4 litros
Explicación paso a paso:
Dado que:
Gasolina consumida = 20 litros
Sea la cantidad de gasolina en el tanque = x
Primera parte del viaje = 2/3 de x
Segunda parte del viaje = 1/2 de (x - 2x / 3)
Cantidad de gasolina en el tanque:
2x / 3 + 1/2 (x - 2x / 3) = 20
Solución para x
2x / 3 + x / 2 - x / 3 = 20
(4x + 3x - 2x) / 6 = 20
5 veces / 6 = 20
5 veces = 20 * 6
5 veces = 120
x = 120/5
x = 24
Cantidad de gasolina en el tanque = 24 litros
Litros consumidos en cada etapa:
Primera parte = 2/3 de 24 = 48/3 = 16 litros
2a parte = 0.5 de (24 - 16) = 0.5 * 8 = 4 litros
The answer would be $3472
Answer:
Step-by-step explanation:
f"(x)=2
integrating
f'(x)=2x+c
f'(1)=2+c=4
c=4-2=2
f'(x)=2x+2
integrating
f(x)=2x^2/2+2x+a
f(x)=x^2+2x+a
f(2)=-2
(2)^2+2(2)+a=-2
4+4+a=-2
a=-2-8=-10
f(x)=x^2+2x-10