If you are looking for the average speed, it is 2m/1 sec.
Assuming it forms a right triangle with the side of the building, you could just use the Pythagorean Theorem to find the height. The ladder would be the hypotenuse, so you would substitute that as c into the equation. The 4 feet could be either a or b; it doesn't really matter. Plug it into (a^2)+(b^2)=(c^2), and you would get. (4^2)+(b^2)=(14^2); simplified, it is (16)+(b^2)=(196). Subtract 16 from 196 to get 180, and you see that (b^2) is equal to 180. Just take the square root of that to get your answer, which would be 6 sqrt5.
The answer would be 1440 feet^2, becasue for area you have to multiply the width, length, and depth. You bascally would draw a 3D rectangle and label the depth, height, and width. That would be your diagram.
It drops 32 feet each second so at six seconds it will have dropped 176 feet
