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Natalija [7]
3 years ago
7

Which equation could represent a circle with a center located at (11,-5)

Mathematics
1 answer:
Anon25 [30]3 years ago
6 0
The standard equation of a circle is:

(x-h)^2-(y-k)^2=r^2 where (h,k) is the center and r is the radius.

We need to make an equation of a circle, whose center is (11,-5) with any radius. Therefore, substitute the value.


(x-h)^2-(y-k)^2=r^2 \\ (11,-5)=(h,k) \\ (x-11)^2-(y-5)^2=64

The bolded part is your answer. Since the radius is not given, we can put any value.

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Step-by-step explanation:

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<u>Given </u><u>:</u><u>-</u>

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<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>

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<u>Answer</u><u> </u><u>:</u><u>-</u>

From the given graph , we can see that the line passes through y axis at (0,5) . So the y intercept is 5 . And the slope of the line is 5/2 = 2.5 . So ,

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Answer: 100 rides are needed to break even.


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Look at the picture.

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