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Natalija [7]
3 years ago
7

Which equation could represent a circle with a center located at (11,-5)

Mathematics
1 answer:
Anon25 [30]3 years ago
6 0
The standard equation of a circle is:

(x-h)^2-(y-k)^2=r^2 where (h,k) is the center and r is the radius.

We need to make an equation of a circle, whose center is (11,-5) with any radius. Therefore, substitute the value.


(x-h)^2-(y-k)^2=r^2 \\ (11,-5)=(h,k) \\ (x-11)^2-(y-5)^2=64

The bolded part is your answer. Since the radius is not given, we can put any value.

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Molly's hair was 20 inches long. Three years later it was 53 inches long. What was the percent increase, to the nearest hundredt
Georgia [21]

Find how much it grew:

53 - 20 = 33 inches.

Divide the amount it grew by the original length

33/20 = 1.65

Subtract 1:

1.65 - 1 = 0.65

Multiply by 100 for percent:

0.65 x 100 = 65%

The percent increase is 65%

4 0
3 years ago
PLS HELP ME ty<br> i know its simple i just need some help on this one
Keith_Richards [23]

Answer:

12t^-6

Step-by-step explanation:

-4 + - 2 = - 6

2*6 = 12

7 0
3 years ago
Find from u.<br><br> -12u = -24
Bingel [31]
Well, to find u, we have to remove all that is attached to it so the equation can just be u=...
   To find u, you have to remove what is attached to it, and that is -12. Then you have to look at the relationship between the -12 and u. The relationship is multiplication, and the opposite of multiplication is division, so all you have to do is divide both sides by -12. So;
-12u/-12=-24/-12
   The -12 cancels the -12, leaving u and the - in 12 cancels the - in 24. Leaving 24/12. And that is 2. Written as;
u=2
   Hope i helped. If you have any more problems, let me know.
5 0
3 years ago
Read 2 more answers
Roberta is thinking about joining the food co-op store. If she pays $10.00 to join, she will get 10% off on all the groceries sh
IceJOKER [234]

$100 worth of groceries.

8 0
3 years ago
What is the solution of the equation? (√2x-1) + 2=x
Gwar [14]

Answer:

x = 5

Step-by-step explanation:

√(2x − 1) + 2 = x

√(2x − 1) = x − 2

2x − 1 = (x − 2)²

2x − 1 = x² − 4x + 4

0 = x² − 6x + 5

0 = (x − 1) (x − 5)

x = 1 or 5

Check for extraneous solutions.

√(2(1) − 1) + 2 = 1

√(1) + 2 = 1

3 = 1

No solution

√(2(5) − 1) + 2 = 5

√(9) + 2 = 5

5 = 5

x = 5

7 0
3 years ago
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