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Natalija [7]
3 years ago
7

Which equation could represent a circle with a center located at (11,-5)

Mathematics
1 answer:
Anon25 [30]3 years ago
6 0
The standard equation of a circle is:

(x-h)^2-(y-k)^2=r^2 where (h,k) is the center and r is the radius.

We need to make an equation of a circle, whose center is (11,-5) with any radius. Therefore, substitute the value.


(x-h)^2-(y-k)^2=r^2 \\ (11,-5)=(h,k) \\ (x-11)^2-(y-5)^2=64

The bolded part is your answer. Since the radius is not given, we can put any value.

You might be interested in
If B is the midpoint of AC, AC=CD, AB=3x+4, AC=11x-17, and CE=49, find DE.
Luba_88 [7]

Answer:

11

Step-by-step explanation:

AB = 3x + 4 and AC which is twice of AB is equal to 11x - 17

2 (3x + 4) = 11x - 17

6x + 8 = 11x - 17

8 + 17 = 11x - 6x

25 = 5x

5 = x

AC = CD = 11x - 17 ➡ 11×5 - 17 = 38

CD = 38 and DE = 49 - 38 = 11

6 0
3 years ago
(2) Mai walked 1/8 of a 30-mile walking trail. How many miles did Mai walk? Explain or show your reasoning. *​
hammer [34]

Answer: 3.75 miles

Step-by-step explanation:

Divide 30 by 8. 30/8= 3.75. If she walked 1/8 then she walked 3.75 miles

5 0
2 years ago
Please help!!!<br>With the pic!!!!
Gekata [30.6K]
1. E
2. C
3. A
4. F
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5 0
2 years ago
Which would be the most appropriate way to estimate -6.1(0.22)? Check all that apply.
tatiyna

Use rounding to get -6(0.2), and then multiply.

Use compatible numbers, such as -6(0.5), and then multiply.

Use front-end estimation to get -6(0.2), and then multiply.

Estimate -6.1(0.22)

Answer:

Use rounding to get -6(0.2), and then multiply.

Use front-end estimation to get -6(0.2), and then multiply.

Round the factors to the nearest whole number, and then multiply.

Step-by-step explanation:

Actual answer:

-6.1(0.22) = -1.342

Estimate answer:

-6 (.2) = 1.2

5 0
2 years ago
what is the surface area of a square pyramid with base side lengths of 10 inches and a slant height of 14 inches
Pavlova-9 [17]

Answer:

The surface area is 380\ in^{2}  

Step-by-step explanation:

we know that

The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces

so

SA=b^{2}+4[\frac{1}{2}(b)(l)]

where

b=10\ in

l=14\ in -----> the slant height

substitute the values

SA=10^{2}+4[\frac{1}{2}(10)(14)]

SA=380\ in^{2}    

5 0
2 years ago
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