It depends on what type of transportation you would be using. If you were walking, it would be reeeaaaalllly slooowww. If a train, <em>much faster!</em>
Answer: the rate at which the distance between the boats is increasing is 68 mph
Step-by-step explanation:
The direction of movement of both boats forms a right angle triangle. The distance travelled due south and due east by both boats represents the legs of the triangle. Their distance apart after t hours represents the hypotenuse of the right angle triangle.
Let x represent the length the shorter leg(south) of the right angle triangle.
Let y represent the length the longer leg(east) of the right angle triangle.
Let z represent the hypotenuse.
Applying Pythagoras theorem
Hypotenuse² = opposite side² + adjacent side²
Therefore
z² = x² + y²
To determine the rate at which the distances are changing, we would differentiate with respect to t. It becomes
2zdz/dt = 2xdx/dt + 2ydy/dt- - - -- - -1
One travels south at 32 mi/h and the other travels east at 60 mi/h. It means that
dx/dt = 32
dy/dt = 60
Distance = speed × time
Since t = 0.5 hour, then
x = 32 × 0.5 = 16 miles
y = 60 × 0.5 = 30 miles
z² = 16² + 30² = 256 + 900
z = √1156
z = 34 miles
Substituting these values into equation 1, it becomes
2 × 34 × dz/dt = (2 × 16 × 32) + 2 × 30 × 60
68dz/dt = 1024 + 3600
68dz/dt = 4624
dz/dt = 4624/68
dz/dt = 68 mph
An angle bisector divides an angle into two equal halves.
The measure of angle
is 70 degrees
The complete question is an illustrates the concept of angle bisector;
Where:
, and line PC bisects 
Because line PC bisects
, then it means that the measure of RPD is twice the measure of CPD:
So, we have:

Substitute 

Divide both sides by 2

Apply symmetric property of equality:

Hence, the measure of angle
is 70 degrees
Read more about angle bisectors at:
brainly.com/question/12896755
For the volume, the formula is length*width*height
so
<span><span><span>(2)</span><span>(1.5)</span></span><span>(1.5)</span></span><span>=<span>4.5
In other words, your answer would be 4.5</span></span>