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kkurt [141]
3 years ago
9

If juliana and brody hiked both trails, how far did they hike? 3 2/3 and 2 5/6

Mathematics
1 answer:
Andreyy893 years ago
8 0

Juliana trails = 3\frac{2}{3}

Brody trails = 2\frac{5}{6}.

In order to find total how far they hiked, we need to add Juliana trails and Brody trails.

Juliana trails + Brody trails  = 3\frac{2}{3} +2\frac{5}{6}.

Adding whole number in front 3+2 = 5.

Now, adding fractions 2/3 and 5/6 by taking common denominator (lcd).

Least common denominator(lcd) of 3 and 6 is = 6.

So, we need to make both denominator = 6.

Muilplying 2/3 by 2 in top and bottom we get 2*2/3*2 = 4/6.

Now, adding 4/6 and 5/6.

We got the common denominator 6. So, we can just add numerators.

\frac{4}{6} +\frac{5}{6}  = \frac{4+5}{6} = \frac{9}{6}

Converting 9/6 into improper fraction:

If we divide 9 by 6, we get quotent 1 and 3 remainder.

So, we get fraction 1 \frac{3}{6} .

3/6 could also be reduced to 1/2 by dividing 3 and 6 by 3.

We get,

\frac{3}{6}  = \frac{1}{2}

Therefore, 1 \frac{3}{6}  = 1 \frac{1}{2}

Adding 5 into 1\frac{1}{2}.

We get,

6\frac{1}{2}.

So, we could say

They hiked total 6\frac{1}{2} far.

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What is 5.316 - 1.942 (show ur work)
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Answer:

3.374

Step-by-step explanation:

\mathrm{Write\:the\:numbers\:one\:under\:the\:other,\:line\:up\:the\:decimal\:points.}

\mathrm{Add\:trailing\:zeroes\:so\:the\:numbers\:have\:the\:same\:length.}

\begin{matrix}\:\:&5&.&3&1&6\\ -&1&.&9&4&2\end{matrix}

\mathrm{Subtract\:each\:column\:of\:digits,\:starting\:from\:the\:right\:and\:working\:left}

\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:6-2=4

\frac{\begin{matrix}\:\:&5&.&3&1&\textbf{6}\\ -&1&.&9&4&\textbf{2}\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\:\:&\:\:&\textbf{4}\end{matrix}}

\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}

\frac{\begin{matrix}\:\:&5&.&3&\textbf{1}&6\\ -&1&.&9&\textbf{4}&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\:\:&\textbf{\:\:}&4\end{matrix}}

\mathrm{The\:bottom\:number\:is\:larger\:than\:the\:upper\:number.\:\:Try\:to\:'borrow'\:a\:digit\:from\:the\:left.}

\mathrm{The\:top\:digit\:is\:not\:bigger\:than\:the\:bottom\:one.\:\:Try\:to\:'borrow'\:a\:digit\:from\:the\:left.}

\frac{\begin{matrix}\:\:&5&.&\textbf{3}&1&6\\ -&1&.&\textbf{9}&4&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\textbf{\:\:}&\:\:&4\end{matrix}}

\mathrm{Borrow\:}1\mathrm{\:from\:}5\mathrm{.\:\:The\:remainder\:is\:}4

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\mathrm{Add\:}1\mathrm{\:ten\:to\:}3:\quad \:10+3=13

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\mathrm{Borrow\:}1\mathrm{\:from\:}13\mathrm{.\:\:The\:remainder\:is\:}12

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\mathrm{Add\:}1\mathrm{\:ten\:to\:}1:\quad \:10+1=11

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\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:4-1=3

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Hence the correct answer is 3.374

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