Answer:
1
Step-by-step explanation:
1/(1+p+q^-1)+1/(1+q+r^-1)+1/(1+r+p^-1) = 1.
350 / 28 = 12.5 gallons, so 13 gallons needed
13 X 2.5 = $32.50
What is the weight of the cow?
D. 14
LL = 1/2 * Hsqrt3
7sqrt3 = 1/2 * ysqrt3
24.25 = ysqrt3
24.25/sqrt3 = y
y = 14
130 (I have to write 20 character or more so I'm writing this)
