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denis-greek [22]
3 years ago
12

Graph the solution for the following linear inequality system. Click on the graph until the final result is displayed.

Mathematics
2 answers:
-Dominant- [34]3 years ago
8 0

Answer:

y ≥ 0  Pic 1

y < x  pic 2

x + y < 6  pic 3

vlada-n [284]3 years ago
8 0

Answer:

<h2>Third graph.</h2>

Step-by-step explanation:

First we have to analyse each restriction and compare with graphs.

The first restriction states that all solutions must be position or zero in the vertical axis, so, the are most only include the upper side of y-axis. So, the second option is not the answer because it's including negative values for <em>y.</em>

The second restriction is a line that cross the point (0,0), and states that every <em>y-value </em>must be less than every corresponding <em>x-values, </em>that means that the area of solution must be under the line that cross (0,0). So, option 1 and 3 are possible solutions.

In addition, the inequality sings < or >, indicate that the border of the solution cannot be solid, which give us the third graph as result.

Therefore, the third graph fulfil all restriction.

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Please help, due today
olga_2 [115]

Answer:

[-8,8]

Step-by-step explanation:

domain is the set of x values that the graph covers

This graph starts at -8 and ends at 8 (including those points and all points between them).

That makes the domain [-8,8]

3 0
3 years ago
Solve for the variable x<br><br> m = -12g + x
mario62 [17]

Answer:

x=m+12g

Step-by-step explanation:

m=-12g+x

making x subject of formula, we have,

x=m+12g

3 0
3 years ago
Is the Mandelbrot set locally connected?
MariettaO [177]

Answer:

Step-by-step explanation:

It is conjectured that the Mandelbrot set is locally connected. This famous conjecture is known as MLC (for Mandelbrot locally connected). By the work of Adrien Douady and John H. Hubbard, this conjecture would result in a simple abstract "pinched disk" model of the Mandelbrot set. In particular, it would imply the important hyperbolicity conjecture mentioned above.

The work of Jean-Christophe Yoccoz established local connectivity of the Mandelbrot set at all finitely renormalizable parameters; that is, roughly speaking those contained only in finitely many small Mandelbrot copies.[19] Since then, local connectivity has been proved at many other points of {\displaystyle M}M, but the full conjecture is still open.

5 0
3 years ago
1. Create a circle. Show and explain the difference between the following:
liberstina [14]
1. 
a.
A secant line is a line which intersects the circle at 2 different points. 

A tangent line is a line which has only one point in common with the circle.

Check picture 1: The orange line s is a secant line, the blue line t is a tangent line.


b.
An inscribed angle is an angle formed by using 3 points of a circle. 

The main property of an inscribed angle is that its measure is half of the measure of the arc it intercepts.

Check picture 2: If  m(\angle KML)=\beta, then the measure of arc KL is 2 \beta.

A central angle is an angle whose vertex is the center of the circle, and the 2 endpoints of the rays are points of the circle.

The main property is: the measure of the central angle is equal to the measure of the arc it intercepts. 

Check picture 2

2.
To construct the inscribed circle of a triangle, we first draw the 3 interior angle bisectors of the triangle.
They meet at a common point called the incenter, which is the center of the inscribed circle.
We open the compass, from the incenter, so that it touches one of the sides at only one point. We then draw the circle. (picture 3)

To draw the circumscribed circle, we first find the midpoints of each side. We then draw perpendicular segments through these (the midpoints.) They meet  at one common point, which is the circumcenter: the center of the circumscribed circle.
We open the compass from the circumcenter to one of the vertices of the triangle. We draw the circle, and see that it circumscribes the triangle.

(picture 4)

3.

Given an equation of a circle: x^2-2x+y^2+6y+6=0.

To determine the center and the radius of the equation we must write the above equation in the form :

                              (x-a)^2+(y-b)^2=r^2.

Then, (a, b) is the center, and r is the radius of this circle. We do this process by completing the square.

Note that x^2-2x becomes a perfect square by adding 1, and 
y^2+6y becomes a perfect square by adding 9. 

Thus we have:

x^2-2x+y^2+6y+6=0\\\\(x^2-2x+1)+(y^2+6y+9)-4=0\\\\(x-1)^2+(y+3)^2=2^2

Thus, the center is (1, -3), and the radius is 2.

4. Not complete


5.

The radius of the pizza is \displaystyle{ \frac{131}{2}ft=65.5ft.

The surface of a circle with radius r is given by the formula \displaystyle{  A=\pi r^2,
and the circumference is given by the formula C=2πr.

Thus, the area of the whole pizza is given by \displaystyle{  A=\pi r^2= \pi\cdot65.5^2=4290.25 \pi (square ft).

Each of the 50 slices, has an area of \displaystyle{ \frac{4290.25 \pi}{50} =85.805 \pi (square ft)

Notice that the perimeter (the crust) of a slice is made of 2 radii, and the arc-like part.
The arc is 1/50 of the circumference, so it is \displaystyle{\frac{2 \pi r}{50} = \frac{2\cdot65.5\cdot \pi }{50}= 2.62 \pi.

So the perimeter of one slice is 65.5+65.5+2.62π=131+2.62π

7 0
3 years ago
Solve the system by substitution.<br> [-2.5x+y = 13.5<br> 12.25x - y=-12.25
IrinaK [193]

Answer:

x = 5/39 , y = 539/39

Step-by-step explanation:

Solve the following system:

{y - 2.5 x = 13.5

12.25 x - y = -12.25

In the first equation, look to solve for y:

{y - 2.5 x = 13.5

12.25 x - y = -12.25

y - 2.5 x = y - (5 x)/2 and 13.5 = 27/2:

y - (5 x)/2 = 27/2

Add (5 x)/2 to both sides:

{y = 1/2 (5 x + 27)

12.25 x - y = -12.25

Substitute y = 1/2 (5 x + 27) into the second equation:

{y = 1/2 (5 x + 27)

1/2 (-5 x - 27) + 12.25 x = -12.25

(-5 x - 27)/2 + 12.25 x = 12.25 x + (-(5 x)/2 - 27/2) = 9.75 x - 27/2:

{y = 1/2 (5 x + 27)

9.75 x - 27/2 = -12.25

In the second equation, look to solve for x:

{y = 1/2 (5 x + 27)

9.75 x - 27/2 = -12.25

9.75 x - 27/2 = (39 x)/4 - 27/2 and -12.25 = -49/4:

(39 x)/4 - 27/2 = -49/4

Add 27/2 to both sides:

{y = 1/2 (5 x + 27)

(39 x)/4 = 5/4

Multiply both sides by 4/39:

{y = 1/2 (5 x + 27)

x = 5/39

Substitute x = 5/39 into the first equation:

{y = 539/39

x = 5/39

Collect results in alphabetical order:

Answer: {x = 5/39 , y = 539/39

5 0
3 years ago
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