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denis-greek [22]
3 years ago
12

Graph the solution for the following linear inequality system. Click on the graph until the final result is displayed.

Mathematics
2 answers:
-Dominant- [34]3 years ago
8 0

Answer:

y ≥ 0  Pic 1

y < x  pic 2

x + y < 6  pic 3

vlada-n [284]3 years ago
8 0

Answer:

<h2>Third graph.</h2>

Step-by-step explanation:

First we have to analyse each restriction and compare with graphs.

The first restriction states that all solutions must be position or zero in the vertical axis, so, the are most only include the upper side of y-axis. So, the second option is not the answer because it's including negative values for <em>y.</em>

The second restriction is a line that cross the point (0,0), and states that every <em>y-value </em>must be less than every corresponding <em>x-values, </em>that means that the area of solution must be under the line that cross (0,0). So, option 1 and 3 are possible solutions.

In addition, the inequality sings < or >, indicate that the border of the solution cannot be solid, which give us the third graph as result.

Therefore, the third graph fulfil all restriction.

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Answer:

C.

Step-by-step explanation:

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r(x)=tan(x) is an odd function since tan(-x)=-tan(x).

s(x)=csc(x) is an odd function since csc(-x)=-csc(x).

So the only contender seems to be C.

Let's check.  To check we have to plug in (-x) in place of (x) and see if we get the same function back since we are looking for an even function.

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Replace (x) with (-x):

f(-x)=\cos(\frac{5\pi}{4}(-x)

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f(x)=\cos(\frac{5\pi}{4}x) since cosine is even; that is cos(-u)=cos(u) where u in this case is \frac{5\pi}{4}x.

So f is even.

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Alborosie
Following PEMDAS

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————

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