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Ludmilka [50]
2 years ago
15

Find the distance between each pair of parallel lines with the guven equation y=2x+7 y=2x-3

Mathematics
1 answer:
Doss [256]2 years ago
4 0

Answer:

10

Step-by-step explanation:

The y-intercept for each line is...

y=2x+7 (0, 7)

y=2x-3 (0, -3)

Note this is because...

y=mx+b

b represents the y-intercept

Using the distance formula...

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2

d=\sqrt{(0-0)^2+(7-(-3))^2

d=\sqrt{0+(10)^2

d=\sqrt{0+100}

d=\sqrt{100}

d=10

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What is 25 divided by 625?
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Christofle is making a doll house the doll house 6/10 meter high without the roof.Thelp roof is 15/100 meter high what will them
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3 years ago
Gabriela Mistral was a poet, diplomat, teacher and humanitarian. Each week she worked a certain amount of days as a poet diploma
Ipatiy [6.2K]

Answer:

Gabriela Mistral works as a humanitarian for 8 days.

Step-by-step explanation:

Gabriela Mistral was a poet, diplomat, teacher and humanitarian such that each week she worked a certain amount of days as a poet diplomat teacher and humanitarian.

Ratio is 1:1:3:2

Let x denotes total number of days Gabriela Mistral work.

As she works 12 days as a teacher,

\frac{3}{7}x=12\\ x=\frac{7}{3}(12)\\ x=28

Total number of days =x=28

So,

she works as a humanitarian for \frac{2}{7}x=\frac{2}{7}(28)=8 days.

6 0
2 years ago
Determine what must be multiplied so that the expression below will have a common denominator. Use the backslash / to type in a
Mashutka [201]

Answer:

Multiply the first fraction by \frac{x+4}{x+4}

Multiply the second fraction by \frac{x-4}{x-4}

Step-by-step explanation:

Given

\frac{4}{x^2 - 16} + \frac{3}{x^2 + 8x + 16}

Required

Make the denominator equal

\frac{4}{x^2 - 16} + \frac{3}{x^2 + 8x + 16}

Factorize the denominator

\frac{4}{x^2 - 4^2} + \frac{3}{x^2 + 4x + 4x+ 16}

\frac{4}{(x - 4)(x + 4)} + \frac{3}{(x+ 4)(x + 4)}

Multiply the first fraction by \frac{x+4}{x+4}

Multiply the second fraction by \frac{x-4}{x-4}

\frac{x+4}{x+4} * \frac{4}{(x - 4)(x + 4)} + \frac{3}{(x+ 4)(x + 4)} * \frac{x-4}{x-4}

\frac{4(x + 4)}{(x - 4)(x + 4)(x + 4)} + \frac{3(x - 4)}{(x+ 4)(x + 4)(x - 4))}

\frac{4(x + 4)}{(x^2 - 16)(x + 4)} + \frac{3(x - 4)}{(x^2 - 16)(x + 4))}

<em>The expression now have the same denominator</em>

7 0
3 years ago
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