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Neko [114]
3 years ago
14

Find the equation of the line that is perpendicular to y = two over three x and contains the point (four,-eight)

Mathematics
1 answer:
Sophie [7]3 years ago
7 0
When it is perpendicular, the slope is the negative reciprocal so it would equal -3/2x. Plug in the points to the equation so you can find the intercept. -8=-3/2(4)+b
Combine: -8=-6+b
Add 6: -2=b
The equation would be f(x)=-3/2x-2
Hope this helped and sorry if I am wrong!
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kolbaska11 [484]

Answer:

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Step-by-step explanation:

                 

3 0
3 years ago
Jake is buying a piece of recycled art from Luna. He started by giving her $50 and promised to pay her $5 a week until he pays t
garri49 [273]

Answer: t = 50 + 5 w

Step-by-step explanation:

Here w shows the number of weeks and t shows the total amount in w weeks.

Since, the initial amount he paid to her = $ 50

After that he paid $ 5 per week.

Thus, the total extra amount he paid = 5 w

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⇒ t = 50 + 5 w

Which is the required relation between the total amount paid(t) and  the number of weeks (w) Jake will take to pay Luna.


6 0
3 years ago
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The table shows a company’s profit based on the number of pounds of food produced.
Bingel [31]

Answer:

$5,300

Step-by-step explanation:

Formulae used,

a=\dfrac{(\sum x^2y\sum xx)-(\sum xy\sum xx^2)}{(\sum xx\sum x^2x^2)-({\sum xx^2)}^2}

b=\dfrac{(\sum xy\sum x^2x^2)-(\sum x^2y\sum xx^2)}{(\sum xx\sum x^2x^2)-({\sum xx^2)}^2}

c=\dfrac{\sum y}{n}-b\frac{\sum x}{n}-a\frac{\sum x^2}{n}

Where,

\sum xx=\sum x^2-\dfrac{(\sum x)^2}{n}

\sum xy=\sum xy-\dfrac{\sum x\sum y}{n}

\sum xx^2=\sum x^3-\dfrac{\sum x\sum x^2}{n}

\sum x^2y=\sum x^2y-\dfrac{\sum x^2\sum y}{n}

\sum x^2x^2=\sum x^4-\dfrac{(\sum x^2)^2}{n}

Putting the values from the table, we get the best fit line as,

y= -0.0817x^2 + 102.24x - 20421

As we want to calculate the profit at 350 pounds, so putting x=350, we get

y= -0.0817(350)^2 + 102.24(350) - 20421=\$5354.75


5 0
4 years ago
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