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Crazy boy [7]
3 years ago
5

What is the greatest common factor of 24s^3 , 12s^4 , and 18s

Mathematics
2 answers:
denpristay [2]3 years ago
6 0
6s. 2 and 3 divide into all these numbers but six is the greatest number that all
Divide into and they all have one s at least.
Illusion [34]3 years ago
5 0
You have to find the number that can be divided into 24,12 and 18. That number would be six. Now we need to look at the exponents s^3 s^4 and s you cant only take out 1 s because 18s doesnt have more than 1 so the final answer would be 6s
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2 years ago
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Read 2 more answers
Convert 2000 Swiss francs to Dutch guilders
Shtirlitz [24]

Answer:

2000 swiss francs equals 3920 Dutch Guilders!

Step-by-step explanation:

One Swiss Franc equals 1.96 Dutch Guilders. Having said this, we can come up with the following equation:

D = 1.96S

Where 'S' represents the swiss francs and 'D' the Dutch Guilders. Now, to convert 2000 Swiss francs, we just need to plug the value into the equation:

D = 1.96(2000) = 3920

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4 0
3 years ago
Camden is going to invest $600 and leave it in an account for 12 years. Assuming the
UkoKoshka [18]

~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$920\\ P=\textit{original amount deposited}\dotfill & \$600\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\dotfill &12 \end{cases}

920=600e^{\frac{r}{100}\cdot 12}\implies \cfrac{920}{600}=e^{\frac{3r}{25}}\implies \cfrac{23}{15}=e^{\frac{3r}{25}}\implies \log_e\left( \cfrac{23}{15} \right)=\log_e\left( e^{\frac{3r}{25}} \right) \\\\\\ \ln\left( \cfrac{23}{15} \right)=\cfrac{3r}{25}\implies 25\cdot \ln\left( \cfrac{23}{15} \right)=3r\implies \cfrac{25\cdot \ln\left( \frac{23}{15} \right)}{3}=r \\\\\\ 3.5620\approx r\implies \stackrel{\%}{3.56}\approx r

7 0
2 years ago
How can i draw this?
mylen [45]
The green arrow thing is a ray. So, question b. is a ray. So the dot would be B and the arrow would be C. 

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3 years ago
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