Question

What is the product?(7x2y3)(3x5y8)

Answer 1

Answer:

The product of $(7x^{2}y^{3})(3x^{5}y^{8})$ is $=21x^{7}y^{11}$

Step-by-step explanation:

We need to find product of expression : $(7x^{2}y^{3})(3x^{5}y^{8})$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}$

$=7y^3\cdot \:3x^{2+5}y^8$

$=7y^3\cdot \:3x^7y^8$

$=7\cdot \:3x^7y^{3+8}$

$=7\cdot \:3x^7y^{11}$

$\mathrm{Multiply\:the\:numbers:}\:7\cdot \:3=21$

$=21x^7y^{11}$

Therefore, the product of $(7x^{2}y^3)(3x^{5}y^{8})$ is $=21x^{7}y^{11}$

Answer 2

$3360y {}^{2}$