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3 years ago

I really need help with this answer

Mathematics

1 answer:

Bond [772]3 years ago

5 0

Answer:

The given two triangles are not congruent.

Step-by-step explanation:

See the diagram of the two triangles attached to this question.

The third angle of the second triangle is [180° - (31° + 124°)] = 180° - 155° = 25°.{Since the other two angles of the triangle are 31° and 124°}

Now, for the first triangle, the values of the adjacent angles of the side with length 6 are 45° and 31°, but for the second triangle, the values of the adjacent angles of the side with length 6 are 25° and 31°.

Therefore, two triangles do not satisfy the Angle=Side-Angle i.e. ASA criteria to become congruent.

So, the given two triangles are not congruent. (Answer)

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Find the sum. r/r^2-q^2 + 5/r+q

pickupchik [31]

Answer:

The answer is:

$\frac{6r-5q}{r^2-q^2}$

which agrees with the last answer option (D) in the list.

Step-by-step explanation:

In order to add rational expressions, we need to express them with the same denominator. Therefore we examine what factors there are in the first denominator, which happens to be a difference of squares which is readily factored out as:

$r^2-q^2=(r+q)\,(r-q)$

the second denominator consists of only one of these factors: $(r+q)$ , then in order to express both rational expressions with the same common denominator, we multiply numerator and denominator of the second fraction by the factor: $(r-q)$

Then we get two expressions that can be easily added as shown below:

$\frac{r}{(r+q)\,(r-q)} +\frac{5\,(r-q)}{(r+q)\,(r-q)} =\frac{r+5(r-q)}{(r+q)(r-q)} =\frac{r+5r-5q}{(r+q)\,(r-q)} =\frac{6r-5q}{r^2-q^2}$

7 0

3 years ago

Help meeeeeeeeeeeee please

vladimir2022 [97]

Answer:

y=2x+4 so C

Step-by-step explanation:

6 0

3 years ago

Can anyone help me fast?

Yanka [14]

Answer:

b=8

Step-by-step explanation:

b²+15²=17²

b²+225=289

b²=289-225

b²=64

b= 8

I hope I helped you^_^

7 0

3 years ago

Read 2 more answers

Determine the solution to the following system of equations: x + y = -3x - y = 1

Zina [86]

Answer:

( -1,-2)

Step-by-step explanation:

x + y = -3

x - y = 1

Add the two equations together to eliminate y

x + y = -3

x - y = 1

------------------

2x = -2

Divide by 2

2x/2 = -2/2

x = -1

Now find y

x+y =-3

-1 +y = -3

-1+1 +y = -3+1

y = -2

( -1,-2)

5 0

3 years ago

How to write (2,5)and(5,11) in point slope form

jekas [21]

First, find the slope 11-5/5-2 =6/3
Then, you plug in (2,5) and 6/3 and then you get your answer!

Answer: y-5= 6/3(x-2)

7 0

4 years ago