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3 years ago

NEED HELP! WILL GIVE BRAINLIEST! PLEASE HELP ME! NO GUESSES!

Mathematics

2 answers:

gulaghasi [49]3 years ago

3 0

Answer:

The answer is A.

Step-by-step explanation:

topjm [15]3 years ago

3 0

The answer is a.

Hope this helps and hope you have a great day

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A sphere and a cylinder have the same radius and height. The volume of the cylinder is 27nft3. Which equation gives the volume o

inna [77]

Answer:

The volume of the sphere is $V=18\pi\ ft^{3}$

Step-by-step explanation:

we know that

The volume of cylinder is equal to

$V=\pi r^{2}h$

we have

$V=27\pi\ ft^{3}$

substitute

$27\pi=\pi r^{2}h$

simplify

$27=r^{2}h$

Remember that

A sphere and a cylinder have the same radius and height

The height of cylinder is equal to the diameter of sphere

h=2r

substitute

$27=r^{2}(2r)$

$13.5=r^{3}$ -----> equation A

The volume of the sphere is equal to

$V=\frac{4}{3}\pi r^{3}$

substitute equation A in the formula of the volume of sphere

$V=\frac{4}{3}\pi (13.5)$

$V=18\pi\ ft^{3}$

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3 years ago

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Michael is taking a survey of students at his high school to find out how many hours they work per week. He surveys all of the s

Fofino [41]

No, he should have surveyed students in his PE class since all grades are represented in that class.

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3 years ago

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Suppose line segment AB has one endpoint at A(0, 0). What are the coordinates of B if (5, 3) is 1/3 of the way from A to B?

prisoha [69]

Answer:

$B(x_2,y_2)= (20,12)$

Step-by-step explanation:

Given

$A = (0,0)$

$Ratio; m : n = 1 : 3$

$Point\ at\ 1 : 3 = (5,3)$

Required

Coordinates of B

This question will be answered using line ratio formula;

$(x,y) = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})$

In this case:

$(x,y) = (5,3)$

$(x_1,y_1) = (0,0)$

$m : n = 1 : 3$

Solving for $(x_2,y_2)$

$(x,y) = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})$ becomes

$(5,3) = (\frac{1 * x_2 + 3 * 0}{1 + 3},\frac{1 * y_2 + 3 * 0}{1 + 3})$

$(5,3) = (\frac{x_2 + 0}{4},\frac{y_2 + 0}{4})$

$(5,3) = (\frac{x_2}{4},\frac{y_2}{4})$

Comparing the right hand side to the left;

$\frac{x_2}{4} = 5$ -- (1)

$\frac{y_2}{4} = 3$ -- (2)

Solving (1)

$x_2 = 5 * 4$

$x_2 = 20$

Solving (2)

$y_2 = 3 * 4$

$y_2 = 12$

Hence;

$B(x_2,y_2)= (20,12)$

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4 years ago

Maximize the objective function P = 2x + 1.5y for the feasible region shown. State the maximum value for P and the ordered pair

umka2103 [35]

Incomplete question. However, let's assume this are feasible regions to consider:

Points:

- (0, 100)

- (0, 125)

- (0, 325)

- (1, 200)

Answer:

Maximum value occurs at 325 at the point (0, 325)

Step-by-step explanation:

Remember, we substitute the points value for x, y in the objective function P = 2x + 1.5y.

- For point (0, 100): P= 2(0) + 1.5 (100) =150

- For point (0, 125): P= 2(0) + 1.5 (125) =187.5

For point (0, 325): P= 2(0) + 1.5 (325) = 487.5

For point (1, 200): P= 2(1) + 1.5 (200) = 302

Therefore, we could notice from the above solutions that at point (0,325) we attain the maximum value of P.

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