Ask question

Ask question

All categories

3 years ago

8

A 2-column table with 5 rows. Column 1 is labeled Number of friends helping with entries 0, 1, 2, 3, 4. Column 2 is labeled Hour

s to build tree house with entries 20, 20 minus 20 (0.10) = 18.0, 18 minus 18 (0.10) = 16.2, 16.2 minus 16.2 (0.10) = 14.6, question mark.
Peter figures he can build the entire tree house by himself in 20 hours. He figures that each additional friend who helps him would improve the time by 10%. He created a table using the algebraic expression n – n(0.10), where n is the previous number of hours.

To the nearest tenth of an hour, how long will it take to build the tree house if 4 friends are helping?

1 answer:

prisoha [69]3 years ago

6 0

Answer:

x y x

Step-by-step explanation:

You might be interested in

Given the points (6, 6) and (-7, -6) find the slope.

ANEK [815]

Answer:

12/13

Step-by-step explanation:

m=(-6-6)/(-7-6)=-12/-13=12/13

5 0

3 years ago

GC = 4x + 5, CF = 3x – 2, and GF = 24. What is the value of x?

Lubov Fominskaja [6]

How old are you is x is hmmm gc 25 cf 6

7 0

3 years ago

Read 2 more answers

Please help with this question

ELEN [110]

Answer:

r^2 * 1/s^4 * t^5

Step-by-step explanation:

r^2 * 1/s^4 * t^5

s^-4 = 1/s^4

7 0

3 years ago

I need help 12 POINTS!!! show work plase

Nesterboy [21]

okay so you have 1/4 and 5 1/2

make 5 1/2 a improper fraction

so you now have 1/4 and 11/2

now do $\frac{1}{4} x\frac{11}{2}$

$\frac{1}{4} x\frac{11}{2} = \frac{11}{8} = 1.375$

I hope this helps you

I feel bad study island is the worst!

3 0

3 years ago

Read 2 more answers

Write the equation of the quadratic function whose graph passes through <img src="https://tex.z-dn.net/?f=%28-3%2C2%29" id="TexF

blagie [28]

Answer:

$f(x)=x^2+3x+2$

Step-by-step explanation:

We want to write the equation of a quadratic whose graph passes through (-3, 2), (-1, 0), and (1, 6).

Remember that the standard quadratic function is given by:

$f(x)=ax^2+bx+c$

Since it passes through the point (-3, 2). This means that when $x=-3$ , $f(x)=f(-3)=2$ . Hence:

$f(-3)=2=a(-3)^2+b(-3)+c$

Simplify:

$2=9a-3b+c$

Perform the same computations for the coordinates (-1, 0) and (1, 6). Therefore:

$0=a(-1)^2+b(-1)+c \\ \\0=a-b+c$

And for (1, 6):

$6=a(1)^2+b(1)+c\\\\ 6=a+b+c$

So, we have a triple system of equations:

$\left\{ \begin{array}{ll} 2=9a-3b+c &\\ 0=a-b+c \\6=a+b+c \end{array} \right.$

We can solve this using elimination.

Notice that the b term in Equation 2 and 3 are opposites. Hence, let's add them together. This yields:

$(0+6)=(a+a)+(-b+b)+(c+c)$

Compute:

$6=2a+2c$

Let's divide both sides by 2:

$3=a+c$

Now, let's eliminate b again but we will use Equation 1 and 2.

Notice that if we multiply Equation 2 by -3, then the b terms will be opposites. So:

$-3(0)=-3(a-b+c)$

Multiply:

$0=-3a+3b-3c$

Add this to Equation 1:

$(0+2)=(9a-3a)+(-3b+3b)+(c-3c)$

Compute:

$2=6a-2c$

Again, we can divide both sides by 2:

$1=3a-c$

So, we know have two equations with only two variables:

$3=a+c\text{ and } 1=3a-c$

We can solve for a using elimination since the c term are opposites of each other. Add the two equations together:

$(3+1)=(a+3a)+(c-c)$

Compute:

$4=4a$

Solve for a:

$a=1$

So, the value of a is 1.

Using either of the two equations, we can now find c. Let's use the first one. Hence:

$3=a+c$

Substitute 1 for a and solve for c:

$\begin{aligned} c+(1)&=3 \\c&=2 \end{aligned}$

So, the value of c is 2.

Finally, using any of the three original equations, solve for b:

We can use Equation 3. Hence:

$6=a+b+c$

Substitute in known values and solve for b:

$6=(1)+b+(2)\\\\6=3+b\\\\b=3$

Therefore, a=1, b=3, and c=2.

Hence, our quadratic function is:

$f(x)=x^2+3x+2$

5 0

3 years ago