Question

If an arithmetic sequence has a 10th term of 17 and a 14th term of 30. find the common difference.​

Answer 1

Answer:

               $\bold{d=\dfrac{13}4=3\dfrac14}$

Step-by-step explanation:

$a_{10}\,,\ _{\{+d\}}\ \ a_{11}\,,\ _{\{+d\}}\ \ a_{12}\,,\ _{\{+d\}}\ \ a_{13}\,,\ _{\{+d\}}\ \ a_{14}\quad\implies\quad\ a_{14}-a_{10}=4d\\\\4d=a_{14}-a_{10}\\\\4d=30-17\\\\4d=13\\{}\ ^{\div4\quad\div4}\\d=\dfrac{13}4=3\dfrac14$