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puteri [66]
3 years ago
8

1. To the nearest ten and the nearest hundred, a store sold about 300 puzzles.

Mathematics
2 answers:
BartSMP [9]3 years ago
5 0

Answer:

B. 279

Step-by-step explanation:

aliya0001 [1]3 years ago
3 0
The answer is B 279 I believe
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What are the focus and directrix of the parabola with the equation y=1/16x^2
Vlada [557]
Y=1/16x^2
multiplying both sides by 16 we get:
16y=x^2
The general form of a parabola is:
(x-h)^2=4p(y-k)
thus
4p=16
p=4
The parabola opens upwrd:
Focus: (h,k-p)
(0,0-4)
=(0,-4)
Directrix: y=-4
8 0
3 years ago
5p - 14 = 8 p + 4 No solution, Infinitely many solutions, 6 ,-6​
DedPeter [7]

Answer:

-6

Step-by-step explanation:

5p - 14 = 8p + 4

Subtract 8p from both sides.

-3p - 14 = 4

Add 14 to both sides.

-3p = 18

Divide both sides by -3.

p = -6

Answer: -6

5 0
3 years ago
I need help please anyone help please
steposvetlana [31]

Answer:

1.

A. 17h+15=c

B. 4

*Steps*

83-15=68

68/17=4

2(box 1):

how to solve: 25m+200=?

m(minutes)=10

25(10)+200=450

*Give me a little to work out the other three please!*

8 0
3 years ago
A jumper in the long-jump goes into the jump with a speed of 12 m/s at an angle of 20° above the horizontal. How far does the ju
weeeeeb [17]

Answer:

x = 9.5 m

Step-by-step explanation:

Given:

This problem is based on 2D motion kinematics equations:

V_0 = 12 m/s

\theta = 20^0

g=9.8 m/s^2

At maximum height:

V_y = 0

Components of initial velocity:

V_0x = V_0 cos (\theta) =(12 )(cos (20^0)) = 11.3 m/s

V_0x = V_0 sin (\theta) = (12)(sin (20^0)) = 4.10 m/s

To find time to reach maximum height:

V_y = V_0y -gt

Plugging in the known values:

0 = 4.10 - 9.8t

t = \frac{-4.10}{-9.8}

t = 0.418 s

Total time = 2t = 2(0.418) = 0.836 s

to find horizontal distance covered:

x = (V_0x)(t)\\x = (11.3)(0.836)\\x = 9.5 m

8 0
3 years ago
PLEASE HELP ME ASAP ill mark you as brainliest
zloy xaker [14]

Answer: 11:  Well ten to the six power is 1000000  so there ya go

12: 250000

Step-by-step explanation:

6 0
3 years ago
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