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avanturin [10]
3 years ago
7

The area of a rectangular vegetable garden is 200 feet. The width is 10 feet. What is the length?

Mathematics
2 answers:
tatuchka [14]3 years ago
8 0

Answer:

20

Explanation:

200  = 20 x 10

Elden [556K]3 years ago
3 0

Answer:

The length is 20 ft. 10ft times 20ft = 200ft^2

Step-by-step explanation:

PLS MARK AS BRAINLIEST

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Quadrilateral ABCD is dilated by a scale factor of 1/3 centered around (1,2). Which statement is true about the dilation
morpeh [17]

Answer:

I cannot help answer this question if you don't add the statements...

Step-by-step explanation:

5 0
3 years ago
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Is x 12 or 15? Or none?
Usimov [2.4K]
The answer is 15 buddy!
7 0
3 years ago
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ABC ≃DEF. Find the lengths of the given sides
GuDViN [60]

Answer:

BC = 8 and EF = 8.

Step-by-step explanation:

Since triangle ABC and DEF are congruent to each other, BC corresponds with EF (as determined by the triangle names).

Set BC and EF equal to each other.

x + 6 = 3x + 2

Subtract x from both sides.

6 = 2x + 2

Subtract 2 from both sides.

4 = 2x.

Divide 2 on both sides.

x = 2.

Substitute 2 for x.

BC = 2 + 6

BC = 8

Since we already know that EF is congruent to BC, EF is also 8.

EC = 3(2) + 2

EC = 6 + 2

EC = 8

5 0
3 years ago
A copy machine makes 28 copies per minute. How many copies does it make in 3 minutes and 45 seconds?
lina2011 [118]
<u>Convert minutes and seconds to minutes:</u>
\text{3 mins 45 seconds} \longrightarrow 3 \dfrac{3}{4} \text{mins}


<u>FInd 3 3/4 mins:</u>
\text{1 min} \longrightarrow 28 \text{ copies}

3  \dfrac{3}{4} \text{ min} \longrightarrow 28 \times 3\dfrac{3}{4} \text{ copies}

3  \dfrac{3}{4} \text{ min} \longrightarrow 28 \times \dfrac{15}{4} \text{ copies}

3  \dfrac{3}{4} \text{ min} \longrightarrow 105 \text{ copies}

Answer: It can make 105 copies.

4 0
4 years ago
Which of the following is not a factor of x^3 – 3x^2 – 4x + 12?
Slav-nsk [51]

Answer:

c. (x + 3)

Step-by-step explanation:

using factor theorem

if x - 3 is a factor then p(a) = 0

p(a)= x^3 - 3x^2 - 4x + 12

a.(x-3)

p(3) = (3)^3 - 3(3)^2 - 4(3) + 12

= 27 - 27 - 12 + 12

= 0

therefore x-3 is a factor

b.(x + 2)

p(-2) = (-2)^3 - 3(-2)^2 - 4(-2) + 12

= -8 -12 + 8 + 12

,= 0

therefore x + 2 is a factor

c.(x + 3)

p(-3) = (-3)^3 - 3(-3)^2 - 4(-3) + 12

= -27 -27 + 12 + 12

= -30

therefore x + 3 is not a factor

d.(x-2)

p(2) = (2)^3 - 3(2)^2 - 4(2) + 12

= 8 -12 - 8 + 12

= 0

therefore x - 2 is a factor

4 0
3 years ago
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