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3 years ago

The area of a rectangular vegetable garden is 200 feet. The width is 10 feet. What is the length?

Mathematics

2 answers:

tatuchka [14]3 years ago

8 0

Answer:

Explanation:

200 = 20 x 10

Elden [556K]3 years ago

3 0

Answer:

The length is 20 ft. 10ft times 20ft = 200ft^2

Step-by-step explanation:

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If two triangles are congruent, which of the following statements must be true? Check all that apply.

bonufazy [111]

Answer:

All statements are correct for two congruent triangles

Step-by-step explanation:

If two triangles are congruent than the rules states that

Triangles are congruent when all corresponding sides and interior angles are congruent. The triangles will have the same shape and size, but one may be a mirror image of the other.

As the fig shows two triangle

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All three corresponding sides of triangle are congruent

all three corresponding angles are congruent

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Xavier Martinez took out a $5,000 loan at 7.5% interest for reconstructing his patio. His monthly payment on the 12-month loan w

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3 years ago

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Micheal has a sink that is shaped like a half-sphere. The sink has a volume of 3000/3π in^3. One day, his sink is clogged. He ha

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A is 27 i think and B is 15 i think

Step-by-step explanation:

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3 years ago

In a test gender selection technique results consisted of 250 baby girls and 234 boys. Based on this result what is the probabil

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3 years ago

What is the solution to the trigonometric inequality 2sin(x)+3>sin ^2(x) over the interval

navik [9.2K]

The intervals that satisfy the given trigonometric Inequality are; 0 ≤ x < 3π/2 and 3π/2 < x ≤ 2π

<h3>How to solve trigonometric inequality?</h3>

We are given the trigonometric Inequality;

2 sin(x) + 3 > sin²(x)

Rearranging gives us;

sin²(x) - 2 sin(x) - 3 < 0

Factorizing this gives us;

(sin(x) - 3)(sin(x) + 1) < 0

Thus;

sin(x) - 3 = 0 or sin(x) + 1 = 0

sin(x) = 3 or sin(x) = -1

sin(x) = 3 is not possible because sin(x) ≤ 1.

Thus, we will work with;

sin(x) = -1 for the interval 0 ≤ x ≤ 2π radians.

Then, x = sin⁻¹(-1)

x = 3π/2.

Now, if we split up the solution domain into two intervals, we have;

from 0 ≤ x < 3π/2, at x = 0. Then;

sin²(0) - 2 sin(0) - 3

= 0² - 0 - 3

= -3 < 0

Thus, the interval 0 ≤ x < 3π/2 is true.

From 3π/2 < x ≤ 2π, take x = 2π. Then;

sin²(2π) - 2 sin(2π) - 3

= 0² - 0 - 3

= -3 < 0

Thus, the interval 3π/2 < x ≤ 2π is also true.

Read more about trigonometric inequality at; brainly.com/question/27862380

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2 years ago