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seraphim [82]
3 years ago
10

Can anyone help and show the work

Mathematics
2 answers:
ankoles [38]3 years ago
6 0

Answer:

Wednesday

Step-by-step explanation:

Fridays temperature was -4

We want a temperature that is 9 degrees lower

-4 -9 = -13

Wednesday has a temperature of -13

OleMash [197]3 years ago
3 0

Answer:

The third option wednesday.

Step-by-step explanation:

on friday it was -4 c. aass the temperature grow in minuses(negatives) it becomes colder. just add 4 and 9 because it tells you that it was colder by nine celsius. higher negative number means lower(colder) temperature. 4+9=13. now add minus to the number we get -13. if you look at the chart this temperature was reported on wednesday. hope i was able to help. ask if need help any further.

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Price-club sells a 12-ounce box of crackers for $2.59 and Shop Mart sells 1-pound box of crackers for $4.68. The unit price at P
Vesna [10]

Answer:

The unit price at Price-Club is $0.2158 per ounce.

The unit price at Shop Mart is $0.2925 per ounce.

Step-by-step explanation:

Price Club:

12-ounce box of crackers for $2.59

So

12 ounces - $2.59

1 ounce - x

12x = 2.59

x = \frac{2.59}{12}

x = 0.2158

The unit price at Price-Club is $0.2158 per ounce.

Shop Mart:

1-pound box of crackers for $4.68.

1 pound is 16 ounces. So

16 ounces - $4.68

1 ounce - x

16x = 4.68

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x = 0.2925

The unit price at Shop Mart is $0.2925 per ounce.

8 0
3 years ago
. 7/8 = /48<br> A. 6<br> B. 1<br> C. 13<br> D. 42
hodyreva [135]
 7/8=x/48

x=(7/8)48
x=(7)(48/8)
x=(7)(6)
x=42
                D.42

4 0
3 years ago
Is apples cost $3.50 per pound how much would one and 1/2 pounds cost
Shalnov [3]

$ 3.50 per lb * 1 1/2 lbs

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It will cost $5.25

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3 years ago
The volume of a right circular cone with radius r and height h is V = pir^2h/3.
Scorpion4ik [409]

The question is incomplete. The complete question is :

The volume of a right circular cone with radius r and height h is V = pir^2h/3. a. Approximate the change in the volume of the cone when the radius changes from r = 5.9 to r = 6.8 and the height changes from h = 4.00 to h = 3.96.

b. Approximate the change in the volume of the cone when the radius changes from r = 6.47 to r = 6.45 and the height changes from h = 10.0 to h = 9.92.

a. The approximate change in volume is dV = _______. (Type an integer or decimal rounded to two decimal places as needed.)

b. The approximate change in volume is dV = ___________ (Type an integer or decimal rounded to two decimal places as needed.)

Solution :

Given :

The volume of the right circular cone with a radius r and height h is

$V=\frac{1}{3} \pi r^2 h$

$dV = d\left(\frac{1}{3} \pi r^2 h\right)$

$dV = \frac{1}{3} \pi h \times d(r^2)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

a). The radius is changed from r = 5.9 to r = 6.8 and the height is changed from h = 4 to h = 3.96

So, r = 5.9  and dr = 6.8 - 5.9 = 0.9

     h = 4  and dh = 3.96 - 4 = -0.04

Now, $dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi (5.9)(4)(0.9)+\frac{1}{3} \pi (5.9)^2 (-0.04)$

$dV=44.484951 - 1.458117$

$dV=43.03$

Therefore, the approximate change in volume is dV = 43.03 cubic units.

b).  The radius is changed from r = 6.47 to r = 6.45 and the height is changed from h = 10 to h = 9.92

So, r = 6.47  and dr = 6.45 - 6.47 = -0.02

     h = 10  and dh = 9.92 - 10 = -0.08

Now, $dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi (6.47)(10)(-0.02)+\frac{1}{3} \pi (6.47)^2 (-0.08)$

$dV=-2.710147-3.506930$

$dV= -6.22$

Hence, the approximate change in volume is dV = -6.22 cubic units

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2 years ago
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Artist 52 [7]

Answer:

It's D I got it right

Step-by-step explanation:

I know

7 0
3 years ago
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