A rectangle has an area of 347.13cm^2 if the length is 20.3cm what is the width of the rectangle

2 answers:

6 0

To find the area of a rectangle, you multiply the length and width together. in this question, they give you the area and the length so you have to find the width. just divide it to find it.

A = l × w

347.13 = 20.3 × w

347.13 ÷ 20.3 = w

17.1 = w

the width is 17.1

hope this helps, God bless!

vivado [14]3 years ago

4 0

347.13^2 = 120499.237

120499.237 / 20.3

= 5935.923

You might be interested in

In a standard normal distribution 95% of the data is within +/- _______standard deviations of the mean.

raketka [301]

Your answer is 2 okay

8 0

3 years ago

Read 2 more answers

What is 8.072 rounded to the nearest hundredths

OlgaM077 [116]

Hundredths = 7
rounded off = 8.07

4 0

3 years ago

Read 2 more answers

7g + 11 subtracted from 12

BlackZzzverrR [31]

A subtracted from b means b-a

7g+11 subtracted from 12 means 12-(7g+11)=12-1(7g+11)=12-7g-11=12-11-7g=1-7g

5 0

2 years ago

TAKE 50 POINTS!!!!!!please Someone HELP.JUST look the picture.

kodGreya [7K]

Step-by-step explanation:

$M=\left[\begin{array}{ccc}1&-1/f_2\\0&1\end{array}\right] \left[\begin{array}{ccc}1&0\\d&0\end{array}\right] \left[\begin{array}{ccc}1&-1/f_1\\0&1\end{array}\right]\\=\left[\begin{array}{ccc}1&-1/f_2\\0&1\end{array}\right]\left[\begin{array}{ccc}1&-1/f_1\\d&-d/f_1\end{array}\right]\\=\left[\begin{array}{ccc}1-d/f_2&-1/f_1+d/f_1f_2\\d&-d/f_1\end{array}\right]\\\\|M|=[-d/f_1+d^2/f_1f_2]-[-d/f_1+d^2/f_1f_2]=0\\\\-1/f=M_{12}=-1/f_1+d/f_1f_2\\1/f=M_{12}=+1/f_1-d/f_1f_2\\$

3 0

3 years ago

A number is totally even if all its digits are even. For instance, the numbers 2022 is totally even. How many four-digit totally

dem82 [27]

Answer:

The units digit of our number should be and can be any of 0, 2, 4, 6 (four opportunities).

The tens digit of our number should be and can be any of 0, 2, 4, 6 (four opportunities).

The hundreds digit of our number should be and can be any of 0, 2, 4, 6, 8 (five opportunities).

The thousands digit of our number should be and can be any of 2, 4, 6 (three opportunities).

So, there are 4*4*5*3 = 16*15 = 240 such 4-digits totally even numbers, satisfying the condition. ANSWER

Step-by-step explanation:

3 0

2 years ago