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3 years ago

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The potential energy function for a system of particles is given byU(x) = −6x3 + 2x2 + 7x,where x is the position of one particl

e in the system.

1 answer:

dexar [7]3 years ago

3 0

Answer: 0

Step-by-step explanation:

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7/8m+9/10-2m-3/5<br> Combine like terms to create an equivalent expression.

stich3 [128]

Answer:

-1.123m+0.3

or in fraction form -9/8m+3/10

Step-by-step explanation:

first you subtract 7/8 from 2

then you subtract again 9/10 from 3/5

4 0

3 years ago

Danes puppy weighd 8oz at birth .The pup weighs 18 times more. So what is his weight now.

katrin [286]

You multiply 18 by 8 and you get 144
so the puppys weight is 144oz now

5 0

3 years ago

Titus works at a hotel. Part of his job is to keep the complimentary pitcher of water at least half full and always with ice. Wh

Alinara [238K]

Answer:

158.33 minutes = 2.63 hours

Step-by-step explanation:

6 0

3 years ago

What is the factored form of the expression?

Georgia [21]

Answer: The answer is (d) $(4x+7)(7x+8).$

Step-by-step explanation: Given equation to be factored is

$28x^2+81x+56.$

The given expression is quadratic, so we can factor it into two linear factors, by using the following factorisation rule.

$x^2+(a+b)x+ab=(x+a)(x+b).$

So, the given equation can be factorised using the above rule. The factorisation is as follows.

$28x^2+81x+56\\\\=28x^2+49x+32x+56\\\\=7x(4x+7)+8(4x+7)\\\\=(4x+7)(7x+8).$

Thus, the correct option is (d).

7 0

3 years ago

Part I: Measuring Parts of a Circle

cluponka [151]

Answer:

case a) The approximate circumference of circle is $5.9\ units$ and the ratio of circumference to Diameter is $\frac{C}{D}=2.95$

case b) The approximate circumference of circle is $6\ units$ and the ratio of circumference to Diameter is $\frac{C}{D}=3$

case c) The approximate circumference of circle is $6.24\ units$ and the ratio of circumference to Diameter is $\frac{C}{D}=3.12$

Step-by-step explanation:

we know that

The approximate circumference of each circle, is equal to the perimeter of each inscribed polygon

case A) the figure is an inscribed pentagon

step 1

Find the approximate circumference of circle

The perimeter of the pentagon is equal to

$P=5s$

where

$s=1.18\ units$

substitute

$P=5(1.18)=5.9\ units$

therefore

The approximate circumference of circle is $5.9\ units$

step 2

Find the ratio of circumference to Diameter

we know that

The radius is half the diameter so

$D=2r=2(1)=2\ units$

The ratio is equal to

$\frac{C}{D}=5.9/2=2.95$

case B) the figure is an inscribed hexagon

step 1

Find the approximate circumference of circle

The perimeter of the hexagon is equal to

$P=6s$

where

$s=1\ units$

substitute

$P=6(1)=6\ units$

therefore

The approximate circumference of circle is $6\ units$

step 2

Find the ratio of circumference to Diameter

we know that

The radius is half the diameter so

$D=2r=2(1)=2\ units$

The ratio is equal to

$\frac{C}{D}=6/2=3$

case C) the figure is an inscribed dodecahedron

step 1

Find the approximate circumference of circle

The perimeter of the dodecahedron is equal to

$P=12s$

where

$s=0.52\ units$

substitute

$P=12(0.52)=6.24\ units$

therefore

The approximate circumference of circle is $6.24\ units$

step 2

Find the ratio of circumference to Diameter

we know that

The radius is half the diameter so

$D=2r=2(1)=2\ units$

The ratio is equal to

$\frac{C}{D}=6.24/2=3.12$

<em>Conclusion</em>

We know that

The exact value of the ratio $\frac{C}{D}$ is equal to

$\frac{\pi D}{D}=\pi$

The approximate value of the circumference will be closer to the real one when the number of sides of the inscribed polygon is greater

4 0

3 years ago