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s344n2d4d5 [400]
3 years ago
7

I need help with d 1 to d 3. I don't understand what to do.

Mathematics
1 answer:
erik [133]3 years ago
3 0
What????

You just add 1 +3 =4
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I need help give real answers
finlep [7]

Answer:

B y = -.001x +100

Step-by-step explanation:

(0,100) (2000,98)

98-100/ 2000-0 = -2/2000 = -1/1000

y-100 = -.001(x -0)

y= -.001x +100

7 0
3 years ago
Graph each function. How is each graph a translation of f(x) = x 2 ?<br> y = x 2 - 5
Shkiper50 [21]
UM i need more details sorry but i dont know it
Ur welcome
A friend trying to help
3 0
3 years ago
What is the midpoint between (3, -1) and (7, -5)?<br> Group of answer choices
Hatshy [7]

Answer:

The answer is

<h2>( 5 , - 3)</h2>

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

<h3>M = (  \frac{x1 + x2}{2} , \:  \frac{y1 + y2}{2} )</h3>

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(3, -1) and (7, -5)

The midpoint is

M = ( \frac{3 + 7}{2}  , \:  \frac{ - 1 - 5}{2} ) \\  = ( \frac{10}{2}  \: , \:  -  \frac{6}{2} )

We have the final answer as

<h3>( 5 , - 3)</h3>

Hope this helps you

6 0
3 years ago
Select all that are undefined csc(pi) cot(pi/2) cot(pi) sec(45 degrees) csc(0 degrees) sec(90 degrees)
lorasvet [3.4K]

Answer:

Csc(pi)

Cot(pi)

Csc(0)

Sec(90)

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
The diameter of steel rods manufactured on two different extrusion machines is being investigated. Two random samples of sizes
devlian [24]

Answer:

(a) There is no evidence to support the claim that the two machines produce rods with different mean diameters.

P-value is 0.818

(b) 95% confidence interval for the difference in mean rod diameter is (-0.17, 0.27).

This interval shows that the difference in mean is between -0.17 and 0.27.

Step-by-step explanation:

(a) Null hypothesis: The two machines produce rods with the same mean diameter.

Alternate hypothesis: The two machines produce rods with different mean diameter.

Machine 1

mean = 8.73

variance = 0.35

n1 = 15

Machine 2

mean = 8.68

variance = 0.4

n2 = 17

pooled variance = [(15-1)0.35 + (17-1)0.4] ÷ (15+17-2) = 11.3 ÷ 30 = 0.38

Test statistic (t) = (8.73 - 8.68) ÷ sqrt[0.38(1/15 + 1/17)] = 0.05 ÷ 0.218 = 0.23

degree of freedom = n1+n2-2 = 15+17-2 = 30

Significance level = 0.05 = 5%

Critical values corresponding to 30 degrees of freedom and 5% significance level are -2.042 and 2.042.

Conclusion:

Fail to reject the null hypothesis because the test statistic 0.23 falls within the region bounded by the critical values -2.042 and 2.042.

There is no evidence to support the claim that the two machines produce rods with different mean diameters.

Cumulative area of test statistic is 0.5910

The test is a two-tailed test.

P-value = 2(1 - 0.5910) = 2×0.409 = 0.818

(b) Difference in mean = 8.73 - 8.68 = 0.05

pooled sd = sqrt(pooled variance) = sqrt(0.38) = 0.62

Critical value (t) = 2.042

E = t×pooled sd/√n1+n2 = 2.042×0.62/√15+17 = 0.22

Lower limit of difference in mean = 0.05 - 0.22 = -0.17

Upper limit of difference in mean = 0.05 + 0.22 = 0.27

95% confidence interval for the difference in mean rod diameter is between a lower limit of -0.17 and an upper limit of 0.27.

3 0
4 years ago
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