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2 years ago

Finish this 1-5 all of it

Mathematics

1 answer:

horrorfan [7]2 years ago

3 0

You are lazy... do it on your own.

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A trapezoid has 8.2 millimeters base and 5.2 millimeters base, as well as 10 millimeters height. What is the area?

Savatey [412]

Answer:

67 mm

Step-by-step explanation:

use area of a trap formula:

b1+b2 /2*h

b1=base

b2=base

h=height

in our case it was, 8.2+5.2/2*10

6 0

2 years ago

Qual o valor de 2 3 -1 3 ?

ra1l [238]

El valor de 23-13 es 10

7 0

2 years ago

R of breaths of all people in asia in 2016? Expressing your answer in scinentific notation in the form a *10^(b) what are the va

Andrew [12]

Answer:

$a = 3.7464$

$b = 16$

Step-by-step explanation:

Given

See attachment for complete question

Required

Express the answer in $a * 10^b$

From the question, we have:

$People = 4.46 * 10^9$

$Breath = 8.4 * 10^6$ breath/person in a year

The number of breath is calculated by:

$Overall = People * Breath$

So, we have:

$Overall = 4.46 * 10^9 * 8.4 * 10^6$

Reorder

$Overall = 4.46 * 8.4* 10^9 * 10^6$

$Overall = 37.464* 10^{9+6}$

$Overall = 37.464* 10^{15}$

Using scientific notation $a * 10^b$ ;

The value (a) must be in the following interval $0 \le a \le 1$

So, we have:

$Overall = 3.7464 * 10 * 10^{15$

$Overall = 3.7464 * 10^{16$

By comparing the above with: $a * 10^b$

$a = 3.7464$

$b = 16$

7 0

2 years ago

The data shown represent the number of runs made each year during Bill Mazeroski’s career. Check for normality.

const2013 [10]

Answer:

The given data is not normal.

Step-by-step explanation:

We are given the following data:

30, 59, 69, 50, 58, 71, 55, 43, 3, 66, 52, 56, 62, 36, 13, 29, 17, 31

Condition for normality:

Mean = Mode = Median

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{800}{18} = 44.44$

Mode is the most frequent observation of the data.

Since all the value appeared once, there is no mode.

$Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}$

Sorted data: 3, 13, 17, 29, 30, 31, 36, 43, 50, 52, 55, 56, 58, 59, 62, 66, 69, 71

Median =

$=\dfrac{9^{th}+10^{th}}{2} = \dfrac{50+52}{2}=51$

Since the mean, mode and median of data are not equal, the data is not normal.

7 0

3 years ago

What is 2•3^4•7^2 in composite form

abruzzese [7]

The answer to that equation is 7938

8 0

3 years ago

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