All categories

3 years ago

6x - 9 = 15 linear equations

Mathematics

2 answers:

gayaneshka [121]3 years ago

7 0

X=4

Add 9 to both sides. 6x=24. Divide 6 from both and get 4.

finlep [7]3 years ago

4 0

Answer:

x = 4

Step-by-step explanation:

6x - 9 = 15

6x - 9 + 9 = 15 + 9

6x = 24

6x / 6 = 24 / 6

x = 4

You might be interested in

What is the volume of this object?

Nastasia [14]

Answer:

Step-by-step explanation:

(Assuming that each cube is 1 unit), the volume is 5 + 6 + 8 which equals 19

7 0

3 years ago

How might you solve a problem that has both a fraction and a decimal in it

Anni [7]

Well, one way is to convert one of the numbers to the other. For example, if I have 3/5 and 0.5, I could convert 3/5 to a decimal. So, I would have 0.6 (3/5 converted to a decimal), and 0.5. Next, I would just add the two together to get my answer of 1.1

5 0

3 years ago

Which expression is equivalent to 8a + 14?<br> 2(2a + 12)<br> 4(4a + 10)<br> 4(2a+8)<br> 2(4a +7)

inessss [21]

Answer is D, 2(4a + 7.)

A is equivalent to 4a + 24.

B is equivalent to 16a + 40.

C is equivalent to 8a + 32.

⭐ Please consider brainliest! ⭐

✉️ If any further questions, inbox me! ✉️

7 0

3 years ago

Which is the correct first step in finding the height of a cylinder with a volume of 178 cubic inches and a radius of 8 inches?

Strike441 [17]

Answer:

Step-by-step explanation:

Ccc

3 0

3 years ago

A teacher was interested in knowing the amount of physical activity that his students were engaged in daily. He randomly sampled

klasskru [66]

Answer:

The standard error of the mean is 4.5.

Step-by-step explanation:

As we don't know the standard deviation of the population, we can estimate the standard error of the mean from the standard deviation of the sample as:

$\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}$

The sample is [30mins, 40 mins, 60 mins, 80 mins, 20 mins, 85 mins]. The size of the sample is n=6.

The mean of the sample is:

$\bar{x}=\frac{1}n} \sum x_i =\frac{30+40+60+80+20+85}{6}=52.5$

The standard deviation of the sample is calculated as:

$s=\sqrt{\frac{1}{n-1}\sum (x_i-\bar x)^2} \\\\ s=\sqrt{\frac{1}{5}\cdot ((30-52.5)^2+(40-52.5)^2+(60-52.5)^2+(80-52.5)^2+(20-52.5)^2+(85-52.5)^2}\\\\s=\sqrt{\frac{1}{5} *3587.5}=\sqrt{717.5}=26.8$

Then, we can calculate the standard error of the mean as:

$\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}=\frac{26.8}{6}= 4.5$

6 0

3 years ago