3x^5+6x^3 PRIME b 3x^4(3x + 2) 3(x^5 + x^3) d 3x^3(x^2 + 2x)
1 answer:
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Answer:
0.2406 = 24.06% probability that exactly two of the selected major customers accept the plan
Step-by-step explanation:
The customers are chosen without replacement, which means that we use the hypergeometric distribution to solve this question.
Hypergeometric distribution:
The probability of x sucesses is given by the following formula:
In which:
x is the number of sucesses.
N is the size of the population.
n is the size of the sample.
k is the total number of desired outcomes.
50 major customers, 15 would accept the plan.
This means that
The utility selects 10 major customers randomly (without replacement) to contact and promote the plan.
This means that
a. What is the probability that exactly two of the selected major customers accept the plan
This is P(X = 2).
0.2406 = 24.06% probability that exactly two of the selected major customers accept the plan
for parabolas, the domain will always be real numbers.
