3x^5+6x^3 PRIME b 3x^4(3x + 2) 3(x^5 + x^3) d 3x^3(x^2 + 2x)
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Given coordinates (1,3) and (0,1).
In order to find the equation of line, we need to find the slope between given coordinates.
We know slope formula,
m=
We have (x1,y1) = (1,3) and (x2,y2) = (0,1).
Plugging values of x1,y1,x2 and y2 in slope formula, we get
Simplifying top and bottom of the fraction we got for slope
We got slope m=2.
We are given second point (0,1), where x-coordinate is 0 and y-coordinate is 1.
y-intercept is a point on y-axis, where x=0.
Therefore, y-intercept = 1.
Now, applying slope-intercept form of the linear equation
y=mx+b, where m is the slope and b is y-intercept.
m=2 and b=1.
Plugging values of m and b in slope-intercept form, we get
y=2x+1.
Therefore, point-slope form for the line is y=2x+1.