Answer:
True
Step-by-step explanation:
Given that a function is

We are to find the slant asymptote if any for this function
Since numerator is of degree 2 and denominator 1, let us divide and then check
Doing long division we find
![f(x)=\frac{1}{2} [x-\frac{5}{2} ]-\frac{11}{4(2x-3)}](https://tex.z-dn.net/?f=f%28x%29%3D%5Cfrac%7B1%7D%7B2%7D%20%5Bx-%5Cfrac%7B5%7D%7B2%7D%20%5D-%5Cfrac%7B11%7D%7B4%282x-3%29%7D)
Thus we find the asymptote y= the quotient obtained i.e
![\frac{1}{2} [x-\frac{5}{2} ]\\=\frac{x}{2} -\frac{5}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5Bx-%5Cfrac%7B5%7D%7B2%7D%20%5D%5C%5C%3D%5Cfrac%7Bx%7D%7B2%7D%20-%5Cfrac%7B5%7D%7B4%7D)
Hence asymptote is

Statement given is true.
Bro same I don't know how to do this maybe cause I don't even care anymore but its OK I hope you got the answer already
F(x) = -5/6x - 3
You can get this by identifying the y-intercept and then using the formula for slope given any two points on the graph.
Area of a square:
(x-2)(x-2)
=(x-2)^2
=x^2-2x-2x+4
=x^2-4x+4 unit sq