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3 years ago

Can someone help answer these for me? ill give brainliest, i really need to finish :(

Mathematics

1 answer:

Elden [556K]3 years ago

6 0

Answer:

Step-by-step explanation:

-8x + 2y = -4 12x - 3y = 4

y = -3x - 2 y = 4x

sub sub

-8x + 2(-3x - 2) = -4 12x - 3(4x) = 4

-8x - 6x - 4 = -4 12x - 12x = 4

-14x = -4 + 4 0 = 4

-14x = 0 NO SOLUTION

x = 0 ========================

y = -3x - 2 -3 + 2y = 5

y = -3(0) - 2 -4x + y = 10...y = 4x + 10

y = -2 sub

solution is : (0,-2) -3 + 2(4x + 10) = 5

================ -3 + 8x + 20 = 5

3x + 2y = 11 8x + 17 = 5

x + 2y = 9...x = 9 - 2y 8x = 5 - 17

sub 8x = - 12

3(9 - 2y) + 2y = 11 x = -12/8

27 - 6y + 2y = 11 x = -3/2

-4y = 11 - 27

-4y = -16 y = 4x + 10

y = -16/-4 y = 4(-3/2) + 10

y = 4 y = -12/2 + 10

y = -6 + 10

x = 9 - 2y y = 4

x - 9 - 2(4) solution (-3/2,4)

x = 9 - 8

x = 1

solution : (1,4)

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Select the correct answer.

NeTakaya

The rational expression that results into x-4/2(x+4) is<em> x²-16/2x+8 * x+4/x²+8x+16</em>

<h3>Multiplying rational expressions</h3>

Rational expressions are written in the form a/b where a and b are integers.

According to the question, we need to determine the expression that is equal to x-4/2(x+4)

From the fourth option;

x²-16/2x+8 * x+4/x²+8x+16

Factorize the quadratic part to have;

x²-16/2x+8 * x²+8x+16/x+4

(x+4)(x-4)/2(x+4) * x+4/(x+4)^2

Cancel out the common expression to have;

x-4 * 1/2(x+4)

x-4/2(x+4)

Hence the rational expression that results into x-4/2(x+4) is<em> x²-16/2x+8 * x+4/x²+8x+16</em>

Learn more rational expression here: brainly.com/question/25292194

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3 0

1 year ago

Which number is a prime number?

Elden [556K]

The answer to this question is 11 because the only way to get 11 in a multiplication problem is multiply it by one which in terms makes it a prime number

8 0

3 years ago

Read 2 more answers

I NEED IMMEDIATE HELP!!!!

DerKrebs [107]

<h2>Hello!</h2>

The answers are:

C) $(3+xz)(-3+xz)$

D) $(y^2-xy)(y^2+xy)$

F) $(64y^2+x^2)(-x^2+64y^2)$

To know which of the products results in a difference of square, we need to remember the difference of squares from:

The difference of squares form is:

$(a+b)(a-b)=a^{2}-b^{2}$

So, discarding each of the given options in order to find which products result in a difference of squares, we have:

$(x-y)(y-x)=xy-x^{2}-y^{2} +yx=-x^{2} -y^{2}$

So, the obtained expression is not a difference of squares.

$(6-y)(6-y)=36-6y-6y+y^{2}=y^{2}-12y+36$

So, the obtained expression is not a difference of squares.

$(3+xz)(-3+xz) =(xz+3)(xz-3)=(xz)^{2}-3xz+3xz-(3)^{2}\\\\(xz)^{2}-3xz+3xz-(3)^{2}=(xz)^{2}-(3)^{2}$

So, the obtained expression is a difference of squares since it matches with the form of the difference of squares.

$(y^2-xy)(y^2+xy)=(y^{2})^{2}+y^{2}*xy-y^{2}*xy-(xy)^{2} \\\\(y^{2})^{2}+y^{2}*xy-y^{2}*xy-(xy)^{2}=(y^{2})^{2}-(xy)^{2}$

So, the obtained expression is a difference of squares since it matches with the form of the difference of squares.

$(25x-7y)(-7y+25x)=-175xy+(25x)^{2}+49y^{2}-175xy\\\\-175xy+(25x)^{2}+49y^{2}-175xy=(25x)^{2}+49y^{2}-350xy$

So, the obtained expression is not a difference of squares

$(64y^2+x^2)(-x^2+64y^2)=(64y^2+x^2)(64y^2-x^2)\\\\(64y^2+x^2)(64y^2-x^2)=(64y^{2})^{2} -(x^{2}*64y^{2})+(x^{2}*64y^{2})-(x^{2})^{2}\\ \\(64y^{2})^{2} -(x^{2}*64y^{2})+(x^{2}*64y^{2})-(x^{2})^{2}=(64y^{2})^{2}-(x^{2})^{2}$