Let's say Bailey takes "b" days to paint it.
and Andrew takes "a" days to paint the same house.
now, Andrew is 6 times faster than Bailey, therefore, if Andrew takes "a" days to do it, Bailey takes then "6a" days, or b = 6a.
now, the year they worked together, they finished it in 7 days.
so, after 1 day then, they have only done 1/7 of the whole work.
and Andrew for one day, has done 1/a of the house, whilst Bailey has done 1/b of the house or 1/(6a).
![\bf \stackrel{\textit{Andrew's rate}}{\cfrac{1}{a}}+\stackrel{\textit{Bailey's rate}}{\cfrac{1}{b}}=\stackrel{\textit{1 day of work}}{\cfrac{1}{7}} \\\\\\ \cfrac{1}{a}+\cfrac{1}{6a}=\cfrac{1}{7}\impliedby \begin{array}{llll} \textit{let's multiply all by }\stackrel{LCD}{42a}\textit{ to toss the}\\ denominators \end{array}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7BAndrew%27s%20rate%7D%7D%7B%5Ccfrac%7B1%7D%7Ba%7D%7D%2B%5Cstackrel%7B%5Ctextit%7BBailey%27s%20rate%7D%7D%7B%5Ccfrac%7B1%7D%7Bb%7D%7D%3D%5Cstackrel%7B%5Ctextit%7B1%20day%20of%20work%7D%7D%7B%5Ccfrac%7B1%7D%7B7%7D%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7B1%7D%7Ba%7D%2B%5Ccfrac%7B1%7D%7B6a%7D%3D%5Ccfrac%7B1%7D%7B7%7D%5Cimpliedby%20%0A%5Cbegin%7Barray%7D%7Bllll%7D%0A%5Ctextit%7Blet%27s%20multiply%20all%20by%20%7D%5Cstackrel%7BLCD%7D%7B42a%7D%5Ctextit%7B%20to%20toss%20the%7D%5C%5C%0Adenominators%0A%5Cend%7Barray%7D)
Answer:
45m^3
Step-by-step explanation:
Given that the area of thee triangle is 3m^2 and the volume formula is b x h x w. You have b x h of the triangle so you just need to multiply by the width of the prism which is 15. 3x15=45
Answer:
![y = \frac{32}{3}](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B32%7D%7B3%7D)
Step-by-step explanation:
Firstly, move over the negative 3/4 fraction (don't forget to swap the operation i.e subtract to add):
![\frac{y}{8} = \frac{7}{12} + \frac{3}{4}](https://tex.z-dn.net/?f=%5Cfrac%7By%7D%7B8%7D%20%3D%20%5Cfrac%7B7%7D%7B12%7D%20%20%2B%20%5Cfrac%7B3%7D%7B4%7D)
Now, to add the two fractions, simply multiply the numerator and denominator by 3:
![\frac{3*3}{4*3} = \frac{9}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B3%2A3%7D%7B4%2A3%7D%20%3D%20%5Cfrac%7B9%7D%7B12%7D)
Now add this to the other fraction:
![\frac{9}{12} + \frac{7}{12} = \frac{16}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B9%7D%7B12%7D%20%2B%20%5Cfrac%7B7%7D%7B12%7D%20%3D%20%5Cfrac%7B16%7D%7B12%7D)
This can be simplified down by dividing both the numerator and denominator by 4:
![\frac{4}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D)
Which now simplifies the original equation to:
![\frac{y}{8} = \frac{4}{3}](https://tex.z-dn.net/?f=%5Cfrac%7By%7D%7B8%7D%20%20%3D%20%5Cfrac%7B4%7D%7B3%7D)
Remove the y out of the fraction:
![\frac{1}{8}y = \frac{4}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B8%7Dy%20%3D%20%5Cfrac%7B4%7D%7B3%7D)
Now multiply both sides by 8:
![(\frac{1}{8}y) * 8 = (\frac{4}{3}) * 8](https://tex.z-dn.net/?f=%28%5Cfrac%7B1%7D%7B8%7Dy%29%20%2A%208%20%3D%20%28%5Cfrac%7B4%7D%7B3%7D%29%20%2A%208)
![y = \frac{4*8}{3}](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B4%2A8%7D%7B3%7D)
![y = \frac{32}{3}](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B32%7D%7B3%7D)
Hope this helps!
I believe x is 104 but I don’t know about y