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3 years ago

For which data sets is the median a better measure of center than the mean?

Mathematics

1 answer:

boyakko [2]3 years ago

6 0

Yes A and C are when its better to use the median than mean as outliers skew the data set

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Suppose that the Celsius temperature at the point (x, y) in the xy-plane is T(x, y) = x sin 2y and that distance in the xy-plane

liraira [26]

Missing information:

How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

Answer:

$Rate = 0.935042^\circ /cm$

Step-by-step explanation:

Given

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$T(x,y) =x\sin2y$

$r = 1m$

$v = 2m/s$

Express the given point P as a unit tangent vector:

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$u = \frac{\sqrt 3}{2}i - \frac{1}{2}j$

Next, find the gradient of P and T using: $\triangle T = \nabla T * u$

Where

$\nabla T|_{(\frac{1}{2}, \frac{\sqrt 3}{2})} = (sin \sqrt 3)i + (cos \sqrt 3)j$

So: the gradient becomes:

$\triangle T = \nabla T * u$

$\triangle T = [(sin \sqrt 3)i + (cos \sqrt 3)j] * [\frac{\sqrt 3}{2}i - \frac{1}{2}j]$

By vector multiplication, we have:

$\triangle T = (sin \sqrt 3)* \frac{\sqrt 3}{2} - (cos \sqrt 3) \frac{1}{2}$

$\triangle T = 0.9870 * 0.8660 - (-0.1606 * 0.5)$

$\triangle T = 0.9870 * 0.8660 +0.1606 * 0.5$

$\triangle T = 0.935042$

Hence, the rate is:

$Rate = \triangle T = 0.935042^\circ /cm$

3 0

2 years ago

Which sampling would be appropriate to survey 120,000 people?

kipiarov [429]

Answer: Id say b

Step-by-step explanation: a would be too high and a bit too detailed. Whereas c and d will be inaccurate.

8 0

3 years ago

Alberta Doan worked 6 hours at time-and-a-half pay and 3 ¼ hours at double-time pay. Her regular pay rate was $9.72 an hour. Wha

natka813 [3]

Answer:

Alberta's total overtime pay of the week was $ 145.80.

Step-by-step explanation:

Given that Alberta worked 6 hours at time-and-a-half pay, and 3 hours at double-time pay, and that the value of her regular work hour is $ 9.72, to determine the value of the pay of his overtime, the following equation must be performed:

6x1.5x9.72 + 3x2x9.72 = X

9x9.72 + 6x9.72 = X

87.48 + 58.32 = X

145.8 = X

Therefore, Alberta's total overtime pay of the week was $ 145.80.

3 0

2 years ago

there are 175 total balloons the ratio of gold to silver balloons is 3:2 how many balloons are gold out of the 175 balloons

egoroff_w [7]

175/3 = 117 gold 58 silver

5 0

2 years ago

Pls help me. its on khan academy

ehidna [41]

i would think it’s 6

8 0

3 years ago

Read 2 more answers