All categories

2 years ago

Solve 5x − 4 = 7 for x using the change of base formula log base b of y equals log y over log b.

Mathematics

1 answer:

Sauron [17]2 years ago

5 0

Answer:

5.209 or A

Step-by-step explanation

5^x-4=7

reserve 4

log sides

x-4 log5 and log7

x-4=log7/log5

+4 or number of your equation

x=log5/log7 +4

use calculator

get answer

5.209

EDIT: Got a 100 on the test this is correct

You might be interested in

Math,math,math,math,math,math

zzz [600]

Answer:

Step-by-step explanation:

MATHHHHHHHH do u need help in math or what?

5 0

2 years ago

Read 2 more answers

What is the coefficient of x2y3 in the expansion of (2x + y)5?

Zigmanuir [339]

Option C:

The coefficient of $x^{2} y^{3}$ is 40.

Solution:

Given expression:

$(2 x+y)^{5}$

Using binomial theorem:

$(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}$

Here $a=2 x, b=y$

Substitute in the binomial formula, we get

$(2x+y)^5=\sum_{i=0}^{5}\left(\begin{array}{l}5 \\i\end{array}\right)(2 x)^{(5-i)} y^{i}$

Now to expand the summation, substitute i = 0, 1, 2, 3, 4 and 5.

$$=\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}+\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1}+\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}+\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}$

$$+\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}+\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}$

Let us solve the term one by one.

$$\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}=32 x^{5}$

$$\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1} = 80 x^{4} y$

$$\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}= 80 x^{3} y^{2}$

$$\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}= 40 x^{2} y^{3}$

$$\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}= 10 x y^{4}$

$$\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}=y^{5}$

Substitute these into the above expansion.

$(2x+y)^5=32 x^{5}+80 x^{4} y+80 x^{3} y^{2}+40 x^{2} y^{3}+10 x y^{4}+y^{5}$

The coefficient of $x^{2} y^{3}$ is 40.

Option C is the correct answer.

5 0

2 years ago

18 is what percent of 60?

anastassius [24]

18 divided by 60 = 0.3
0.3 x 100 = 30
18 is 30% of 60

7 0

2 years ago

Will works 7 hours a day, 6 days a week.

exis [7]

A day
= £9.20x7
= £64.40

6 days
£64.40x6= £386.40

The wages he has after he shared it with his mom
£386.40/7x5
= 55.20x5
= £276

£1932/£276= 7

It will take him 7 weeks to afford a car worth £1932.

6 0

2 years ago

How to write 30000+300+3 in standard form

Elis [28]

Answer:

30303

Step-by-step explanation:

math bro

7 0

3 years ago