1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
OleMash [197]
3 years ago
6

Solve 5x − 4 = 7 for x using the change of base formula log base b of y equals log y over log b.

Mathematics
1 answer:
Sauron [17]3 years ago
5 0

Answer:

5.209 or A

Step-by-step explanation

5^x-4=7

reserve 4

log sides

x-4 log5 and log7  

x-4=log7/log5

+4 or number of your equation

x=log5/log7 +4

use calculator

get answer

5.209

EDIT: Got a 100 on the test this is correct

You might be interested in
A statistics textbook chapter contains 60 exercises, 6 of which are essay questions. A student is assigned 10 problems. (a) What
Scilla [17]

Answer:

a) P=0.3174

b) P=0.4232

c) P=0.2594

d) The shape of the hypergeometric, in this case, is like a binomial with mean np=1.

Step-by-step explanation:

The appropiate distribution to model this is the hypergeometric distribution:

P(X=x)=\frac{\binom{s}{x}\binom{N-s}{M-x}}{\binom{N}{M}}=\frac{\binom{6}{x}\binom{54}{10-x}}{\binom{60}{10}}

a) What is the probability that none of the questions are essay?

P(X=0)=\frac{\binom{6}{0}\binom{54}{10-0}}{\binom{60}{10}}\\\\P(X=0)=\frac{1*(54!/(10!*44!)}{60!/(10!*50!)} =\frac{2.3931*10^{10}}{7.5394*10^{10}} = 0.3174

b)  What is the probability that at least one is essay?

P(X=1)=\frac{\binom{6}{1}\binom{54}{9}}{\binom{60}{10}}\\\\P(X=1)=\frac{6*(54!/(9!*43!)}{60!/(10!*50!)} =\frac{3.1908*10^{10}}{7.5394*10^{10}} =0.4232

c) What is the probability that two or more are essay?

P(X\geq2)=1-(P(0)+P(1))=1-(0.3174+0.4232)=1-0.7406=0.2594

8 0
3 years ago
Brainliest for right answer!!!
Verizon [17]
Let y=x+6 be equation 1...
Replace equation 1 in equation 2
X+6 =-2x-3
X+2x = -3 -6
3x = -9
X = -3
3 0
3 years ago
Read 2 more answers
Find the solutions to the equation below. check all that apply
BartSMP [9]

Answer:

A and E

Step-by-step explanation:

Given

20x² - 26x + 8 = 0 ( divide through by 2 )

10x² - 13x + 4 = 0

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 10 × 4 = 40 and sum = - 13

The factors are - 5 and - 8

Use these factors to split the x- term

10x² - 5x - 8x + 4 = 0 ( factor the first/second and third/fourth terms )

5x(2x - 1) - 4(2x - 1) = 0 ← factor out (2x - 1) from each term

(2x - 1)(5x - 4) = 0

Equate each factor to zero and solve for x

2x - 1 = 0 ⇒ 2x = 1 ⇒ x = \frac{1}{2} → E

5x - 4 = 0 ⇒ 5x = 4 ⇒ x = \frac{4}{5} → A

6 0
3 years ago
A function() is graphed
eduard
Y=mx+b use that formula
6 0
3 years ago
What is the percent increase when 7,200 increases by 1,800?
Nuetrik [128]

Answer:

B.

Step-by-step explanation:

The percent increase when 7200 increases by 1800 is 25 %

8 0
3 years ago
Read 2 more answers
Other questions:
  • What is the area of the composite figure?<br><br><br> _______ cm2<br><br> pls and ty
    10·2 answers
  • A 3-foot-tall mailbox casts a shadow that is 1.8 feet long. At the same time, a nearby street lamp casts a shadow that is 12 fee
    13·1 answer
  • What is the solution for x in the equation?<br><br> 10x − 4.5 + 3x = 12x − 1.1
    7·2 answers
  • a. At the beginning of the year, Addison Company’s assets are $300,000 and its equity is $100,000. During the year, assets incre
    14·1 answer
  • Which equation represents a line that has a slope of 1/3 and passes through point (-2, 1)?
    13·1 answer
  • A replacement value for an open sentence is ​
    15·1 answer
  • What is the product of 2.2 + 0.3d- 4
    13·2 answers
  • Duncan has the space to plant, at most, 24 flower bulbs in his garden. Daffodil bulbs cost $3 each, and tulip bulbs cost $2 each
    5·1 answer
  • Help algebra 2 please
    7·1 answer
  • R(6 1/2)=5(6 1/2) - 3.5
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!