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OleMash [197]
3 years ago
6

Solve 5x − 4 = 7 for x using the change of base formula log base b of y equals log y over log b.

Mathematics
1 answer:
Sauron [17]3 years ago
5 0

Answer:

5.209 or A

Step-by-step explanation

5^x-4=7

reserve 4

log sides

x-4 log5 and log7  

x-4=log7/log5

+4 or number of your equation

x=log5/log7 +4

use calculator

get answer

5.209

EDIT: Got a 100 on the test this is correct

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Answer:

Step-by-step explanation:

a) 5 cm(25000)(1 m/100 cm)(1 km/1000 m) = 1.25 km

b) 2.2 km (1000 m/km)(100 cm/m) / 25000 = 8.8 cm

6 0
3 years ago
Find the areas of the sectors formed by ZDFE. Round your answers to the nealest hundredth.
Sonja [21]

Answer:

Step-by-step explanation:

Area of the sector is modeled by the expression = \frac{\theta}{360}(\pi ) r^{2}

Here, θ = central angle subtended by the arc

r = Radius of the circle

Area of the red sector = \frac{137}{360}(\pi)(28)^{2}

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3 0
3 years ago
Solving a Quadratic Equation by Completing the Square Solve x2 + 8x = 33 by completing the square. Which is the solution set of
tresset_1 [31]
Divide the coefficient of x by 2 then square the quotient.
Add the result to both sides of the equation.

x^2 + 8x = 33
x^2 + 8x + (\frac{8}{2})^2 = 33 + (\frac{8}{2})^2
x^2 + 8x + 4^2 = 33 + 4^2
x^2 + 8x + 16 = 33 + 16
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Factor the left-hand side.

(x + 4)^2 = 49

Square both sides.

x + 4 = \sqrt{49}

Subtract both sides by 4.

x = -4± \sqrt{49}

Simplify.

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NOTE: You're probably seeing a strange A in the equations. I tried to fix it, but I couldn't. Sorry about that.
8 0
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Read 2 more answers
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Answer:

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Step-by-step explanation:

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Simplify the expression

\hookrightarrow \sf \:  {a}^{ \frac{1}{3} -  \frac{1}{4}  }

Transform the Expression

\hookrightarrow \sf \:  {a}^{ \frac{4 - 3}{12}  }

Calculate

\hookrightarrow \sf {a}^{\frac{1}{12}}

3 0
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Ugo [173]

Answer:

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<em>\frac{6}{60}</em>

<em>they</em><em> </em><em>can </em><em>perform</em>

<em>\frac{3}{60} work in60 \: minutes \div 3</em>

<em>so</em><em> </em><em>the</em><em> </em><em>can</em><em> </em><em>per</em><em>form</em><em> </em>

<em>\frac{6}{60} work \: in \: 20minutes \times 2</em>

<em>the</em><em> </em><em>take</em><em> </em><em>6</em><em> </em><em>hou</em><em>rs</em><em> </em><em>and</em><em> </em><em>4</em><em>0</em><em> </em><em>minu</em><em>tes</em>

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