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jolli1 [7]
3 years ago
13

Find all factors of 618

Mathematics
2 answers:
azamat3 years ago
7 0

Answer:

1, 2, 3, 6, 103, 206, 309, 618

Step-by-step explanation:

They can all divide 618.

AfilCa [17]3 years ago
5 0

Answer:

1, 2, 3, 6, 103, 206, 309, 618

Step-by-step explanation:

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Two Step Inequality Math problems
juin [17]

Answer:

answer choice a is correct, and no

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
For the function f(x)=5x^3-6, find f^-1
max2010maxim [7]

Answer:

f^{-1} means the inverse function

f^{-1} = \sqrt[3]{(x + 6)/5}

Step-by-step explanation:

f^{-1} means the inverse function

to find an inverse function, flip the x and y variables and solve for y

f(x) = 5x^3 - 6

y = 5x^3 - 6

x = 5y^3 - 6

x + 6 = 5y^3

(x + 6)/5 = y^3

\sqrt[3]{(x + 6)/5} = y

5 0
3 years ago
PLEASE HELP Solve the right triangle.<br> Round your answers to the nearest tenth.
HACTEHA [7]
I think A equals 44 degrees
7 0
3 years ago
Read 2 more answers
suppose that incomes of families in Newport Harbor are normally distributed with a mean of $750,000 and a standard deviation of
denis23 [38]

Answer: 0.345

Step-by-step explanation:

Given : The incomes of families in Newport Harbor are normally distributed with Mean : \mu=\$ 750,000 and Standard deviation : \sigma= $250,000

Samples size : n=4

Let x be the random variable that represents the incomes of families in Newport Harbor.

The z-statistic :-

z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}

For x= $800,000

z=\dfrac{800000-750000}{\dfrac{250000}{\sqrt{4}}}=0.4

By using the standard normal distribution table , we have

The probability that the average income of these 4 families exceeds $800,000 :-

P(x>80,000)=P(z>0.4)=1-P(z\leq0.4)\\\\=1-0.6554217=0.3445783\approx0.345

Hence, the probability that the average income of these 4 families exceeds $800,000 =0.345

6 0
4 years ago
Seth says 10 divided by 5.49 equals 1.82 is he correct?
Savatey [412]
Yes. 
He rounded it. 
The exact answer is 1.82149362477
4 0
4 years ago
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