Answer:
The area of triangle K is 16 times greater than the area of triangle J
Step-by-step explanation:
we know that
If Triangle K is a scaled version of Triangle J
then
Triangle K and Triangle J are similar
If two triangles are similar, then the ratio of its areas is equal to the scale factor squared
Let
z -----> the scale factor
Ak ------> the area of triangle K
Aj -----> the area of triangle J
so

we have

substitute



therefore
The area of triangle K is 16 times greater than the area of triangle J
Answer:
x^2y / 4
Step-by-step explanation:
x^4 y^4 / 4x^2 y^3
x^4 / x^2 = x^2 and y^4 / y^3 = y so:
this = x^2y / 4
Answer:
V≈628.32
Step-by-step explanation:
If they intersect eachother then the answer is true
Answer:
32x^25
Step-by-step explanation:
4x^14*8x^11