Answer:
1. 1/2(x - 3)³
2. 3x/y²
Step-by-step explanation:
1. to simplify, we could just FOIL the equations out, but since this is a division, we can cancel out any common factors in the numerator and the denominator to make it easier
2(x - 3)³
----------
4(x- 3)^6
what do these two have in common? both have a (x - 3)³ to start off, so we can cancel out the (x - 3)³ in the numerator, and take the diference in the denominator which gives us (x - 3)³
2(x - 3)³ / (x - 3)³ = 2
4(x - 3)^6 / (x - 3)³ = 4(x - 3)³
so now we have:
2
-----
4(x - 3)³
we can simplify 2/4 and get 1/2 so now we have the following:
1
--------
2(x - 3)³
there is nothing else to simplify, so this is the final answer
2. to solve 8x/y² - 5x/y², we see they both have <em>like denominators</em>, this means that we can just combine the terms over one denominator and we get the following:
8x - 5x
----------
y²
we can subtract 5x from 8x because both have an x in them and are therefore able to be subtracted
8x - 5x = 3
so the final answer is 3x/y²
Hey there!
If two angles are supplementary, that means that the measures of the two angles have a sum of 180.
If the two angles were of equal measure, they would both be 90 degrees.
The easiest way to get this would be to subtract 12 degrees from one 90 degree angle and add them to the other 90 degree angle so one angle has 24 more degrees then the other.
90 - 12 = 78
90 + 12 = 102
Let's check to make sure this works.
102 + 78 = 180 That checks out.
102 - 24 = 78 That also works.
So, the measures of the angles are 102 and 78.
Hope this helps!
<span>3.14(a2 + ab)
=3.14(4^2 + 4*2)
=3.14(16+8)
=3.14(24)
=75.36</span>
Answer:
Step-by-step explanation:
A man steps out of a plane at 4,000m of height above the ground.The point at which he jumps out of the plane would make a good reference point. However, if his acceleration is going to change as a result of him opening his parachute 2000m above the ground, a good reference point would be there. Keep in mind though, that his velocity at that instant would need to be known for it to be useful- otherwise the airplane reference point would be just as good with appropriate modeling....
