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xeze [42]
3 years ago
15

Find the length of the unknown side. Round your answer to the nearest whole number.

Mathematics
2 answers:
aleksley [76]3 years ago
6 0
The answer is 72.8. in order to solve this problem, you need to use the pythagorean theorem. the equation is c^2-b^2=a^2.

75^2-18^2=a^2

75 squared minutes 18 squared is 5301. then you need to find the square root of 5301.

the square root of 5301 is 72.8079666, rounding to 72.8.
AlladinOne [14]3 years ago
3 0
The answer is 72.8 and you are welcome have a great day
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My score in math is a 69 pls help
Xelga [282]

Answer:

okay

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
two swimmers swam lobstering practice together the swim 175 laps swmmier b swam 25 more than twice as many as swimmer a how many
qwelly [4]

Answer:

swimmer b swims 100 yards. approximately how many more feet did swimmer a swim than swimmer b? 2.

Step-by-step explanation:

6 0
2 years ago
Using the bijection rule to count binary strings with even parity.
AleksandrR [38]

Answer:

Lets denote c the concatenation of strings. For a binary string <em>a</em> in B9, we define the element f(a) in E10 this way:

  • f(a) = a c {1} if a has an odd number of 1's
  • f(a) = a c {0} if a has an even number of 1's

Step-by-step explanation:

To show that the function f defined above is a bijective function, we need to prove that f is well defined, injective and surjective.

f   is well defined:

To see this, we need to show that f sends elements fromo b9 to elements of E10. first note that f(a) has 1 more binary integer than a, thus, it has 10. if a has an even number of 1's, then f(a) also has an even number because a 0 was added. On the other hand, if a has an odd number of 1's, then f(a) has one more 1, as a consecuence it will have an even number of 1's. This shows that, independently of the case, f(a) is an element of E10. Thus, f is well defined.

f is injective (or one on one):

If a and b are 2 different binary strings, then f(a) and f(b) will also be different because the first 9 elements of f(a) form a and the first elements of f(b) form b, thus f(a) is different from f(b). This proves that f in injective.

f is surjective:

Let y be an element of E10, Let x be the first 9 elements of y, then f(x) = y:

  • If x has an even number of 1's, then the last digit of y has to be 0, and f(x) = x c {0} = y
  • If x has an odd number of 1's, then the last digit of y has to be a 1, otherwise it wont be an element of E10, and f(x) = x c {1} = y

This shows that f is well defined from B9 to E10, injective, and surjective, thus it is a bijection.

3 0
3 years ago
Please help with A, B, and C
makkiz [27]
A. 75 degrees because the angle creates by the car and the opposite 75 degree are vertical angles meaning that their congruent
B. 75 degrees because the 4the street and the 3rd streets are both Patel meaning that the angle of the car and the 75 degree angle on northeast angle of the fourth street are corresponding angels
C. 105 degrees because the 180 degrees which is the angle of a straight line subtracted from the 75 degree gives the answer of 105 degrees

4 0
3 years ago
The graph of function f is shown above. if g(x)=x^2/f(x) what is the value of g'(1)?​
Alla [95]

Answer:

Step-by-step explanation:

Find the equation of the segment going from (0,-5) to (3,7)

y intercept = -5

Slope = (-5 - 7) / (0 - 3) = -12/-3 = 4

equation: y = 4x - 5

g(x) = x^2 / f(x)

f(x)=  (4x - 5)

g(x) = x^2 / (4x - 5)

g'(x) = x^2 * (4x - 5)^-1

g'(x) = 2x*(4x - 5)^-1  + (-1) *4* x^2 (4x - 5)^-2

I will leave that monster the way it is and just find g'(1)

g'(1) = 2(1) * (4(1) - 5)^-1    +    (-1) (1)^2 *4* (4(1) - 5)^-2

g'(1) = 2(1) * (-1)^-1             +    (-1) (1)^2 *4 * (-1)^2

g'(1) = -2                      +        (-1) (1)^2 (4)

g'(1) = - 2                     +        (-1) (1)^2 (4)

g'(1) =  - 2 - 4

g'(1) = - 6

7 0
3 years ago
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