Answer:
- using the rule given: 2.5
- using an exponential rule: 7
Step-by-step explanation:
Evaluating the linear rule given, for n = 1, we have ...
a1 = 7(1/2)(1) -1 = 7/2 -1 = 5/2 = 2.5
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We suspect you may intend the exponential function ...
an = 7(1/2)^(n-1)
Then, for n = 1, we have ...
a1 = 7(1/2)^(1 -1) = 7(1) = 7 . . . . the first term is 7
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When writing an exponential expression in plain text, it requires the exponential operator, a caret (^). If the exponent contains any arithmetic, as this one does, it must be enclosed in parentheses.
Let X be the number of lightning strikes in a year at the top of particular mountain.
X follows Poisson distribution with mean μ = 3.8
We have to find here the probability that in randomly selected year the number of lightning strikes is 0
The Poisson probability is given by,
P(X=k) = 
Here we have X=0, mean =3.8
Hence probability that X=0 is given by
P(X=0) = 
P(X=0) = 
P(X=0) = 0.0224
The probability that in a randomly selected year, the number of lightning strikes is 0 is 0.0224
Answer:
Paul
Step-by-step explanation:
Paul earn more than monica. Though he is getting less interest but because of his higher initial amount he is getting more return.
Computing the return of both
Monica return is 100*3.4%= $3.4 in a year
Paul return is 200*%2.2= $4.4 in a year.
( (r+2) * (2r-9)-(r^2+17r+30) )/(r+2)
none of the parenthetical operations or power operations can be simplified further, so multiplication and division first, left to right:
(2r(r+2) -9(r+2) - r^2 + 17r +30)/(r+2)
(2r^2 + 2r -9r+18 -r^2 +17r +30 )/(r+2)
(r^2 +10r +48)/(r+2)
